Answer:
x = 2000 cameras
Step-by-step explanation:
C(x) Total cost in producing x units
C- = C(x) /x Average cost of producing x units x > 0
Cannon Precision Instrument
C (x) Total monthly cost for producing x units of M1 cameras
is C(x) = 0.0025x² + 80x + 10000
Then average cost of producing x cameras M1 is
C-(x) = ( 0.0025x² + 80x + 10000) /x
C-(x) = 0.0025x + 80 + 10000/x
Taking derivatives on both sides of the equation
C-´(x) = 0.0025 - 10000/x²
Then
C-´(x) = 0
( 0.0025x² - 10000 ) / x² = 0
0.0025x² - 10000 = 0
x² = 10000 /0.0025 x² = 4000000
x = 2000 cameras
-3
25
180
-1
SOS HELP MAYDAY MADAY WER3E GOING DOWN BRUDDAS WE DONT KNOW DA WAE
<span>4b^2 - 16 = (2b + 4)(2b - 4)
</span>difference of squares<span>
a^</span>2<span> – b^</span>2<span> = (a + b)(a – b) </span><span>
</span>
Answer:
482
Step-by-step explanation:
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