How far did the frog jump? the answer is one of the solutions of the quadratic equation

because that's where the frogs height is 0 (y=0) feet.
Use your favorite formula for quadratic equations. I got two solutions: 0 and 30. 0 is clearly the starting point and 30 feet is point where the frog lands.
The height is the maximum of the quadratic form. Use the formula for maximum x of a quadratic: xmax = -b/(2a) = -0.51/(2*0.017) = 15. The maximum at that point is ymax = 3.825
So, the correct answer is (a) 30 ft far and 3.83 high.
Steps:
1: Pulling out like terms/factors
2: Trying to factor as a Difference of Squares
Description:
Let's simplify step-by-step.
20x⁵y²/5 x -3 y⁷
=4x⁶y²−3y⁷
Answer: =4x⁶y²−3y⁷
Please mark brainliest
<em><u>Hope this helps.</u></em>
Answer: B.
Step-by-step explanation: TVM Solver Equation:
N = 216 (12 x 18 years)
I% = 3.5
PV = 0
PMT = - $350
FV = 105,106.7593
P / Y = 12 (months)
C / Y = 12
PMT: END
<u>Given</u>:
Given that the side length of the base of the square pyramid is 16 inches.
The height of the pyramid is 22.1 inches.
We need to determine the volume of the square pyramid.
<u>Volume of the square pyramid:</u>
The volume of the square pyramid can be determined using the formula,

where B is the area of the base and h is the height of the pyramid.
Substituting B = (16 × 16) and h = 22.1, we get;




Thus, the volume of the pyramid is 1885.9 cubic inches.