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4 years ago

HELP ASAP PLZ ;-;

Mathematics

1 answer:

mart [117]4 years ago

5 0

Answer:

1. (x^3+7x^2+8x-16) ; domain: R (all real number)

2. (x-1) ; domain: R-(-4) {all real number except (-4)

Step-by-step explanation:

f*g= f(x) and g(x)

i.e, f*g= (x^2+3x-4)(x+4)

i.e, f*g= x^3+3x^2-4x+4x^2+12x-16

i.e, f*g=x^3+7x^2+8x-16

it's domain is R, i.e, all real number!

f/g=(x^2+3x-4)/(x+4)

i.e, f/g={(x+4)(x-1)}/4

i.e,f/g=x-1

it's domain is all real number,except the number at which (x+4) becomes 0, i.e, x= (-4), -4 is not in domain!

✌️;)

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Which of the following is equivalent to x + 1/y ÷ g + 1/h

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2 years ago

Write in word form 300+10+2

sineoko [7]

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3 years ago

Read 2 more answers

What value of x makes the equation -4x – (-3 − 5x) = -3(2x − 8) true?.

zzz [600]

Answer:

x=3

Step-by-step explanation:

-4x-(-3-5x)=-3(2x-8)

-4x+3+5x=-6x+24

x+3=-6x+24

+6x +6x

7x+3=24

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-hope it helps

7 0

3 years ago

Verify that:

Lelu [443]

Answer:

See Below.

Step-by-step explanation:

Problem 1)

We want to verify that:

$\displaystyle \left(\cos(x)\right)\left(\cot(x)\right)=\csc(x)-\sin(x)$

Note that cot(x) = cos(x) / sin(x). Hence:

$\displaystyle \left(\cos(x)\right)\left(\frac{\cos(x)}{\sin(x)}\right)=\csc(x)-\sin(x)$

Multiply:

$\displaystyle \frac{\cos^2(x)}{\sin(x)}=\csc(x)-\sin(x)$

Recall that Pythagorean Identity: sin²(x) + cos²(x) = 1 or cos²(x) = 1 - sin²(x). Substitute:

$\displaystyle \frac{1-\sin^2(x)}{\sin(x)}=\csc(x)-\sin(x)$

Split:

$\displaystyle \frac{1}{\sin(x)}-\frac{\sin^2(x)}{\sin(x)}=\csc(x)-\sin(x)$

Simplify:

$\csc(x)-\sin(x)=\csc(x)-\sin(x)$

Problem 2)

We want to verify that:

$\displaystyle (\csc(x)-\cot(x))^2=\frac{1-\cos(x)}{1+\cos(x)}$

Square:

$\displaystyle \csc^2(x)-2\csc(x)\cot(x)+\cot^2(x)=\frac{1-\cos(x)}{1+\cos(x)}$

Convert csc(x) to 1 / sin(x) and cot(x) to cos(x) / sin(x). Thus:

$\displaystyle \frac{1}{\sin^2(x)}-\frac{2\cos(x)}{\sin^2(x)}+\frac{\cos^2(x)}{\sin^2(x)}=\frac{1-\cos(x)}{1+\cos(x)}$

Factor out the sin²(x) from the denominator:

$\displaystyle \frac{1}{\sin^2(x)}\left(1-2\cos(x)+\cos^2(x)\right)=\frac{1-\cos(x)}{1+\cos(x)}$

Factor (perfect square trinomial):

$\displaystyle \frac{1}{\sin^2(x)}\left((\cos(x)-1)^2\right)=\frac{1-\cos(x)}{1+\cos(x)}$

Using the Pythagorean Identity, we know that sin²(x) = 1 - cos²(x). Hence:

$\displaystyle \frac{(\cos(x)-1)^2}{1-\cos^2(x)}=\frac{1-\cos(x)}{1+\cos(x)}$

Factor (difference of two squares):

$\displaystyle \frac{(\cos(x)-1)^2}{(1-\cos(x))(1+\cos(x))}=\frac{1-\cos(x)}{1+\cos(x)}$

Factor out a negative from the first factor in the denominator:

$\displaystyle \frac{(\cos(x)-1)^2}{-(\cos(x)-1)(1+\cos(x))}=\frac{1-\cos(x)}{1+\cos(x)}$

Cancel:

$\displaystyle \frac{\cos(x)-1}{-(1+\cos(x))}=\frac{1-\cos(x)}{1+\cos(x)}$

Distribute the negative into the numerator. Therefore:

$\displaystyle \frac{1-\cos(x)}{1+\cos(x)}=\displaystyle \frac{1-\cos(x)}{1+\cos(x)}$

3 0

3 years ago

PLEASE HELP 80 POINTS!!

motikmotik

Answer:

Bagel

plain

Tuna Eggs Chicken salad Cream cheese butter

Poppy

Tuna Eggs Chicken salad Cream cheese butter

Wheat

Tuna Eggs Chicken salad Cream cheese butter

There are 15 combinations because tuna, eggs, chicken salad, cream cheese, and butter = 5

there are 3 different types of bagels plain poppy and wheat. with this information you can tell that the 5 combinations x 3 bagel types equal 15 total

7 0

4 years ago

**HELP ASAP PLZ ;-;**

HELP ASAP PLZ ;-;