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Lyrx [107]
3 years ago
7

What is the pythagorean theorem formula

Mathematics
1 answer:
murzikaleks [220]3 years ago
6 0
<span> pythagorean theorem formula= </span> a^{2}+ b^{2}= c^{2} 
You might be interested in
How on earth do u do this?
11111nata11111 [884]

Answer:

  ΔABC ≅ ΔZXN

Step-by-step explanation:

Find the letters of the matching parts of the triangles.

A is the right angle; as is Z.

B is the angle where 10 meets 26; as is X.

C is the remaining angle; as is N.

__

Corresponding vertices are listed in the same order:

  ΔABC ≅ ΔZXN

4 0
4 years ago
What is 6(36,200)-(21)(8,050)?
coldgirl [10]
I'm guessing these problems are meaning multiplication in which you need to multiply them but don't worry here is your answer. 

6 * 36,200 = (217,200) 
 
21 * 8,050 = (169,050)

Subtract your totals which gives you (48,150) is your answer! 

Hope this helps. 
Have a great day!!!
6 0
3 years ago
A line passing through which of the following pairs of coordinates represents a proportional relationship? A. (1, 3) and (2, 6)
trasher [3.6K]

Answer:

Answer is A - (1, 3) and (2, 6)

Step-by-step explanation:

(1, 3) • 2

= (1 • 2, 3 • 2)

= (2, 6)

Ratio: 2/2, 6/2

Therefore, the answer is A.  

3 0
3 years ago
Read 2 more answers
10. Determine whether or not, vectors ui(1,-2, 0, 3), u2 = (2, 3,0,-1), u3 = (3,9,-4,-2) e R is a linear combination of the (2,-
vodka [1.7K]

If (2, -1, 2, 1) is a linear combination of the three given vectors, then there should exist c_1,c_2,c_3 such that

(2,-1,2,1)=c_1(1,-2,0,3)+c_2(2,3,0,-1)+c_3(3,9,-4,-2)

or equivalently, there should exist a solution to the system

\begin{cases}c_1+2c_2+3c_3=2\\-2c_1+3c_2+9c_3=-1\\-4c_3=2\\3c_1-c_2-2c_3=1\end{cases}

Right away we get c_3=-\dfrac12, so the system reduces to

\begin{cases}c_1+2c_2=\dfrac72\\\\-2c_1+3c_2=\dfrac72\\\\3c_1-c_2=0\end{cases}

Notice that the first equation is the sum of the latter two. The third equation gives us

3c_1-c_2=0\implies 3c_1=c_2

so that in the second equation,

-2c_1+3c_2=\dfrac72\implies7c_1=\dfrac72\implies c_1=\dfrac12

which in turn gives

3c_1=c_2\implies c_2=\dfrac32

and hence the (2, -1, 2, 1) is a linear combination of the given vectors, with

\boxed{(2,-1,2,1)=\dfrac12(1,-2,0,3)+\dfrac32(2,3,0,-1)-\dfrac12(3,9,-4,-2)}

5 0
4 years ago
Use the diagram shown.
vazorg [7]

Answer:

ΔCFG is an isosceles triangle.

Step-by-step explanation:

From the picture attached,

From ΔABF and ΔEDG,

Conditions for ΔABF and ΔEDG by SSS property of congruence,

1). AB ≅ DE [Given]

2). (BC + CF) = (DF + CG)

CF = CG [Given → BC = DF]

3). FA ≅ EG

(AG + GF) ≅ (EF + GF)

AG ≅ EF

Since, two sides of ΔCFG are equal in measure

ΔCFG is an isosceles triangle.

7 0
3 years ago
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