
As we know ~
Area of the circle is :

And radius (r) = diameter (d) ÷ 2
[ radius of the circle = half the measure of diameter ]
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<h3>Problem 1</h3>



Now find the Area ~




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<h3>problem 2</h3>



Bow, calculate the Area ~




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<h3>Problem 3 </h3>




・ .━━━━━━━†━━━━━━━━━.・
<h3>Problem 4</h3>



now, let's calculate area ~



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<h3>problem 5</h3>



Now, let's calculate area ~




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<h3>problem 6</h3>




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Answer:
( 400-x)/3
Step-by-step explanation:
Total chocolate chips Savannah had = 400
Number of chocolate chips she saved for garnishing =x
Number of chocolate chips remain = 400-x
Number of brownie pans = 3
Chocolate chips were spread evenly in 3 pans,
Chocolate chips were in each pan of brownies =( 400-x)/3
Step-by-step explanation:

The standard form: Ax + By = C.
The point-slope form:

7. We have the points (4, -7) and (2, -3). Substitute:

8. We have the points (1, 5) and (-10, -6). Substitute:

Answer:C = 49 sq. units
Step-by-step explanation:
Multiply 7 by 14 to get 98
Then divide 98 by 2 to get that obtuse triangle's area; 49 sq. units