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Svet_ta [14]
4 years ago
13

To rent a certain meeting room, a college charges a reservation fee of $47 and an additional fee of $9.30 per hour. The film clu

b wants to spend at most $93.50 on renting the meeting room. What are the possible amounts of time for which they could rent the meeting room?
Use t for the number of hours the meeting room is rented, and solve your inequality for t.
Mathematics
1 answer:
dexar [7]4 years ago
4 0
The total number of hours is 5
Why?
equation = 9.30x + 47 = 93.50
9.30x + ( 47 - 47 ) = 93.50 - 47 = 46.5
(9.30x / 9.30) = 46.5 / 9.30 = 5
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- 3x + y = 3<br> 2y = -3x - 12
Lynna [10]

Answer:

x=-2, y=-3

Step-by-step explanation:

we can rearrange the questions to make it easier

y=3x+3

2y=-3x-12

if you add the two equations, you get

3y=0x-9

so y=-9/3 = -3

plug y into one of the equations

-3=3x+3

-6=3x

x=-2

and then check your work by plugging into the other equation:

2*-3=-3(-2)-12

-6=6-12

-6=-6

8 0
3 years ago
Can AAA prove triangle similarity?
pashok25 [27]

Answer: yes

Step-by-step explanation: if any two angles of a triangle are equal to any two angles of another triangle then the two triangles are similar to eachother

3 0
2 years ago
Find the value of x ​
Lelu [443]

refer the attachment for your answer !!

4 0
3 years ago
Read 2 more answers
8. Based on the multiplication rule for independent events, what is the probability of getting an airplane in both boxes? Explai
Furkat [3]

Answer:

P(A and B ) = \frac{1}{4}* \frac{1}{4}=\frac{1}{16}

Step-by-step explanation:

We assume the following problem: "Consider the following ways students might create their lists using the notation:

B for block, W for watch, R for ring, and A for airplane.  The first letter represents the toy found in the first box, and the second letter represents the toy found in the second  box. The first column represents getting the block in the first box, followed by each one of the other toys. The  second column represents getting the watch in the first box, followed by each one of the other toys. The third  column is developed with the ring in the first box, and the fourth column is developed with the airplane in the first  box"

And the possible outcomes are:

BB WB RB AB

BW WW RW AW

BR WR RR AR

BA WA RA AA

As we can see we have 16 possibilities.

For this case if we use the independence of events we have the following rule. If A and B are independent events then:

P(A and B) = P(A) *P(B)

Let A = Select an airplane  from the total of 4 for the first box

B= Select an airplane from the total of 4 for the second box

For this case probability of getting an airplane selected in the  first box is 1 out of 4 since we have just one outcome possible and 4 possible.

P(A) = \frac{1}{4}

And the probability of getting an airplane selected in the second box is also 1/4 since for the first box selected we have the same number of optiosn for the second box , 4.

P(B) = \frac{1}{4}

So then we have this:

P(A and B ) = \frac{1}{4} \frac{1}{4}=\frac{1}{16}

5 0
4 years ago
PLEASE HELP SOLVE FOR Y
alexgriva [62]

Hello!

\large\boxed{y = 5(\frac{1}{2})^{x} }

Recall that the equation of an exponential graph is:

y = a(b)^{x}

We can see from the graph there is a y-intercept at y = 5. Plugging in 0 for x results in:

5 = a(b)^{0}\\\\5 = a(1)\\\\a = 5

Solve for b by plugging in another point on the graph:

10 = 5(b)^{-1}\\\\2 = b^{-1}\\\\b = 1/2

Write the final equation:

y = 5(\frac{1}{2})^{x}

6 0
3 years ago
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