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3 years ago

How many numbers from 300 to 899 contain atleast one four

Mathematics

2 answers:

Brut [27]3 years ago

8 0

I think the answer could be 1199

svetlana [45]3 years ago

3 0

The awnser is about 50

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There are 13 brunettes and 7 blondes in a Spanish class. The teacher selects two students to run an errand. How many possible ou

Delicious77 [7]

Answer:

91 possible outcomes

Step-by-step explanation:

As the teacher selects a brunette followed by a blonde, we just need to find the number of possibilities of choosing a brunnette and the number of possibilities of choosing a blonde:

number of possibilities of choosing a brunette: 13

number of possibilities of choosing a blonde: 7

Then, the number of possible outcomes is the product of these number of possibilities:

13 * 7 = 91 possible outcomes

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3 years ago

Which of the following ordered pairs could represent the x-intercept of a function?

Murrr4er [49]

Answer:

Step-by-step explanation:

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3 years ago

What is also know as a linear system

kicyunya [14]

Answer:

Two or more linear equations in the same variables; also called a linear system. ... A linear system with infinitely many solutions. System of Linear Inequalities. Consists of two or more linear inequalities in the same variable.

3 0

2 years ago

Which of the following numbers does not belong here? 64, 16, 36, 32, 8, 4

Harman [31]

Hello! 36 does not belong in the pattern. The pattern is multiply by 2, but 36 doesn’t belong, because half of it is 18 and 18 is not an option. The other numbers go together to make that pattern of multiplying by 2. The answer is 36.

8 0

3 years ago

The total claim amount for a health insurance policy follows a distribution with density function 1 ( /1000) ( ) 1000 x fx e− =

gizmo_the_mogwai [7]

Answer:

the approximate probability that the insurance company will have claims exceeding the premiums collected is $\mathbf{P(X>1100n) = 0.158655}$

Step-by-step explanation:

The probability of the density function of the total claim amount for the health insurance policy is given as :

$f_x(x) = \dfrac{1}{1000}e^{\frac{-x}{1000}}, \ x> 0$

Thus, the expected total claim amount $\mu$ = 1000

The variance of the total claim amount $\sigma ^2 = 1000^2$

However; the premium for the policy is set at the expected total claim amount plus 100. i.e (1000+100) = 1100

To determine the approximate probability that the insurance company will have claims exceeding the premiums collected if 100 policies are sold; we have :

P(X > 1100 n )

where n = numbers of premium sold

$P (X> 1100n) = P (\dfrac{X - n \mu}{\sqrt{n \sigma ^2 }}> \dfrac{1100n - n \mu }{\sqrt{n \sigma^2}})$

$P(X>1100n) = P(Z> \dfrac{\sqrt{n}(1100-1000}{1000})$

$P(X>1100n) = P(Z> \dfrac{10*100}{1000})$

$P(X>1100n) = P(Z> 1) \\ \\ P(X>1100n) = 1-P ( Z \leq 1) \\ \\ P(X>1100n) =1- 0.841345$

$\mathbf{P(X>1100n) = 0.158655}$

Therefore: the approximate probability that the insurance company will have claims exceeding the premiums collected is $\mathbf{P(X>1100n) = 0.158655}$

4 0

2 years ago