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Otrada [13]
3 years ago
10

Add. Simplify your answer. 2/11 + 6/11

Mathematics
2 answers:
Margaret [11]3 years ago
5 0
The answer is probably like 8/11
wel3 years ago
4 0
Okay the denominator stays the same. Add across the top 2+6= 8 . so put 8 over 11 and you can't simplify it is at its lowest term. 8/11
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Suppose 56 gallon came out of a pipe in 8 minutes what was the rate per gallon
Vera_Pavlovna [14]

Answer:

7 gallons per 1 minute

Step-by-step explanation:

56/8=7

right?

4 0
3 years ago
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Find all the zeros of the polynomial function p(x) = x3 – 5x2 + 33x – 29
hram777 [196]

Answer:

\large \boxed{\sf \ \ x=1, \ \ x=2+5i, \ \ x=2-5i \ \ }

Step-by-step explanation:

Hello,

I assume that we are working in \mathbb{C}, otherwise there is only one zero which is 1. Please consider the following.

First of all, <u>we can notice that 1 is a trivial solution</u> as

   p(1) = 1^3-5\cdot 1^2 + 33\cdot 1-29=1-5+33-29=0

It means that (x-1) is a factor of p(x) so we can find two real numbers, a and b, so that we can write the following.

p(x)=(x-1)(x^2+ax+b)=x^3+ax^2+bx-x^2-ax-b=x^3+(a-1)x^2+(b-a)x-b

Let's identify like terms as below.

a-1 = -5 <=> a = -5 + 1 = -4

b-a = 33

-b = -29 <=> b = 29

So

\boxed{ \ p(x)=(x-1)(x^2-4x+29) \ }

Now, we need to find the zeroes of the second factor, meaning finding x so that:

x^2-4x+29=0 \ \text{ complete the square, 29 = 25 + 4}  \\ \\  x^2-2\cdot 2 \cdot x+2^2+25=0 \\ \\ (x-2)^2=-25=(5i)^2 \ \text{ take the root } \\ \\x-2=\pm 5i \ \text{ add 2 } \\ \\  x = 2+5i \ \text{ or } \ x = 2-5i

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

5 0
3 years ago
I’ll mark you brainlist
kherson [118]

Answer:

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Step-by-step explanation:

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Y_Kistochka [10]

Answer:

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Step-by-step explanation:

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3 years ago
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What is cos of negative pi/3?<br> what is sin of negative pi/3?
stellarik [79]
Pi/3 is equivalent to 60 degrees, as 2pi is equal to 360 degrees. cos(60) in a triangle yields 1/2, and sin(60) yields (3^(1/2))/2. Thus, -pi/3, or -60 degrees would be a fourth quadrant point on the unit circle and these values would be negative as well, at cos(-pi/3)=-1/2 and sin(-pi/3)=-(3^(1/2))/2 
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