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3 years ago

10

suppose you choose a marble from a bag containing 5 red marbles, 4 white marbles, and 5 blue marbles. you return the first marbl

e to the bag and then choose again.

1 answer:

Semenov [28]3 years ago

5 0

The denominator would still be the same you placed the marble back into the bag

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You have 15 pennies in your pocket. Of those pennies, 3 are Canadian. Suppose you pick a penny out of your pocket at random. Fin

den301095 [7]

The best and most correct answer among the choices provided by your question is the fourth choice or letter D. The probability is 4/5.

<span>P ( canadian)= 3/15 = 1/5
On the other hand, P (not canadian) = 1 - 1/5 = 4/5</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly.

4 0

3 years ago

Debra plans to invest $2,250 for 10 years. She can invest in a savings account that pays 4% simple intrest or a savings account

Diano4ka-milaya [45]

Answer:

$\$180.55$

Step-by-step explanation:

step 1

<u><em>Simple interest</em></u>

we know that

The simple interest formula is equal to

$A=P(1+rt)$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

$t=10\ years\\ P=\$2,250\\r=4\%=4/100=0.04$

substitute in the formula above

$A=2,250(1+0.04*10)$

$A=2,250(1.4)$

$A=\$3,150$

step 2

<u><em>Interest compounded annually</em></u>

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=10\ years\\ P=\$2,250\\r=4\%=4/100=0.04\\n=1$

substitute in the formula above

$A=2,250(1+\frac{0.04}{1})^{1*10}$

$A=2,250(1.04)^{10}$

$A=\$3,330.55$

step 3

Find the differences between the two final amounts

$A=\$3,330.55-\$3,150=\$180.55$

5 0

3 years ago

Gavin rented a truck for 5 days. The truck

NeX [460]

$55x5 days= $275
$285.20-275=$10.20
10.20/.15= 68
Answer= 68 miles

7 0

3 years ago

Solve the right triangle, ΔABC, for all the missing side and angles to the nearest tenth given sides a = 10.6 and b = 19.2.

Aliun [14]

Answer:

Part 1) $c=21.9\ units$

Part 2) $B=61.1\°$

Part 3) $A=28.9\°$

Part 4) $C=90\°$

Step-by-step explanation:

step 1

Find the length side c

Applying the Pythagoras Theorem

$c^{2}=a^{2}+b^{2}$

substitute the given values

$c^{2}=10.6^{2}+19.2^{2}$

$c^{2}=481$

$c=21.9\ units$

step 2

Fin the measure of angle B

we know that

In the right triangle

$tan(B)=b/a$

substitute the given values

$tan(B)=19.2/10.6$

$B=arctan(19.2/10.6)=61.1\°$

step 3

Find the measure of angle A

we know that

The measure of interior angles in a triangle must be equal to 180 degrees

so

∠A+∠B+∠C=180°

Remember that in a right triangle the measure of angle C is 90 degrees

we have

$B=61.1\°$

$C=90\°$

substitute

$A+61.1\°+90\°=180\°$

$A=28.9\°$

4 0

3 years ago

In analyzing the city and highway fuel efficiencies of many cars and trucks, the mean difference in fuel efficiencies for the 60

Olegator [25]

Answer:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

Step-by-step explanation:

Data provided

$\bar X=7.38$ represent the sample mean for the fuel efficiencies

$\mu$ population mean

s=2.51 represent the sample standard deviation

n=601 represent the sample size

Confidence interval

The formula for the confidence interval of the true mean is given by:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom for this case is given by:

$df=n-1=601-1=600$

The Confidence level for this case is 0.95 or 95%, and the significance level $\alpha=0.05$ and $\alpha/2 =0.025$ and the critical value is given by $t_{\alpha/2}=1.96$

Replcing into the formula for the confidence interval is given by:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

8 0

3 years ago