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3 years ago

Help me so confused?

Mathematics

2 answers:

adell [148]3 years ago

8 0

6. That's a rhombus, so the meet of the diagonals is their midpoint, the diagonals are perpendicular and the sides are congruent. So GH=GE/2 and DH are the legs of a right triangle with hypotenuse GD=GF. So

$GF = \sqrt{GH^2 + DH^2} = \sqrt{(42/2)^2 + (16)^2} = \sqrt{697}$

Answer: √697

7. Same story, this time we have hypotenuse EF=13, one leg FH=DF/2=9 so other leg

$EH = \sqrt{EF^2-FH^2} = \sqrt{13^2 - 9^2} = \sqrt{88} = 2 \sqrt{22}$

Answer: 2√22

Schach [20]3 years ago

4 0

GE=42 divide that by 2 to get GH=21, HE=21

DH=16 that is half of line DF, so HF=16 too

so GF would be 21+16=37

EF=13 DF=18 divide 18 by 2 and get DH=9 and HF=9

since HF=9 do 13-9=4 so EH=4

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Jose buys cookies and oranges at the store. He pays a total of \$49.82 He pays a total of $4.81 for the cookies . He buys 7 bags

Ierofanga [76]

Answer:

7x+4.81=49.82x

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3 0

3 years ago

Which expression represents "five less than three times x"?

natulia [17]

three times x = 3 × x = 3x

less 5 means subtract 5 from 3x, hence

3x - 5 → A

4 0

3 years ago

Read 2 more answers

A 20-sided regular polygon has an angle measure represented as 3gº.

Andre45 [30]

The value of g in the 20 sided regular polygon is 54.

<h3>How to find the angles of a regular polygon?</h3>

If all the polygon sides and interior angles are equal, then they are known as regular polygons.

The polygon given is a 20 sided regular polygon and the measure of each angle is 3g degrees.

Therefore, let's find g.

The sum of interior angles of a 20 sided polygon is as follows:

180(n - 2) = 180(20 - 2) = 180(18) = 3240

Therefore,

each angle = 3240 / 20 = 162

Hence,

162 = 3g

g = 162 / 3

Therefore,

g = 54

learn more on regular polygon here: brainly.com/question/16992545

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8 0

1 year ago

Use stoke's theorem to evaluate∬m(∇×f)⋅ds where m is the hemisphere x^2+y^2+z^2=9, x≥0, with the normal in the direction of the

ludmilkaskok [199]

By Stokes' theorem,

$\displaystyle\int_{\partial\mathcal M}\mathbf f\cdot\mathrm d\mathbf r=\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S$

where $\mathcal C$ is the circular boundary of the hemisphere $\mathcal M$ in the $y$ - $z$ plane. We can parameterize the boundary via the "standard" choice of polar coordinates, setting

$\mathbf r(t)=\langle 0,3\cos t,3\sin t\rangle$

where $0\le t\le2\pi$ . Then the line integral is

$\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=0}^{t=2\pi}\mathbf f(x(t),y(t),z(t))\cdot\dfrac{\mathrm d}{\mathrm dt}\langle x(t),y(t),z(t)\rangle\,\mathrm dt$
$=\displaystyle\int_0^{2\pi}\langle0,0,3\cos t\rangle\cdot\langle0,-3\sin t,3\cos t\rangle\,\mathrm dt=9\int_0^{2\pi}\cos^2t\,\mathrm dt=9\pi$

We can check this result by evaluating the equivalent surface integral. We have

$\nabla\times\mathbf f=\langle1,0,0\rangle$

and we can parameterize $\mathcal M$ by

$\mathbf s(u,v)=\langle3\cos v,3\cos u\sin v,3\sin u\sin v\rangle$

so that

$\mathrm d\mathbf S=(\mathbf s_v\times\mathbf s_u)\,\mathrm du\,\mathrm dv=\langle9\cos v\sin v,9\cos u\sin^2v,9\sin u\sin^2v\rangle\,\mathrm du\,\mathrm dv$

where $0\le v\le\dfrac\pi2$ and $0\le u\le2\pi$ . Then,

$\displaystyle\iint_{\mathcal M}\nabla\times\mathbf f\cdot\mathrm d\mathbf S=\int_{v=0}^{v=\pi/2}\int_{u=0}^{u=2\pi}9\cos v\sin v\,\mathrm du\,\mathrm dv=9\pi$

as expected.

7 0

3 years ago

What is 469.890 rounded to the nearest tenth??

ASHA 777 [7]

Answer:

470

Step-by-step explanation:

every thing that is above 5 you go up one tenth.

Anything lower than five you keep the same tenth.

3 0

3 years ago