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4 years ago

A parabola is represented by the equation y2 = 5x. Which equation represents the directrix?

Mathematics

2 answers:

scoray [572]4 years ago

8 0

Answer:

$x=-\frac{5}{4}$

Step-by-step explanation:

Given equation,

$y^2=5x-----(1)$

Which is the equation of a parabola along x-axis,

From equation (1),

$(y-0)^2=\frac{4}{4}\times 5(x-0)$

$(y-0)^2=4(\frac{5}{4})(x-0)-----(2)$

We know that, the standard form of a parabola along x-axis is,

$(y-k)^2=4p(x-h)$

Where, the directrix is,

x = h-p

By comparing equation (2),

The directrix of the given parabola is,

$x = 0 - \frac{5}{4}\implies x = -\frac{5}{4}$

zalisa [80]4 years ago

4 0

Answer:

On ed its x = -5/4

Step-by-step explanation:

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bonufazy [111]

Answer:

option c is correct.

Step-by-step explanation:

$7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{16x}\right)-3\left(\sqrt[3]{8x}\right)$

WE need to simplify this equation.

Solve the parenthesis of each term.

$=7\left\sqrt[3]{2x}\right-3\left\sqrt[3]{16x}\right-3\left\sqrt[3]{8x}\right$

Now, We will find factors of the terms inside the square root

factors of 2: 2

factors of 16 : 2x2x2x2

factors of 8: 2x2x2

Putting these values in our equation: $=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2X2 x}\right)-3\left(\sqrt[3]{2X2X2 x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3*2\left(\sqrt[3] {2 x}\right)-3*2\left(\sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)$

Adding like terms we get:

$=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right\\=(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\$

$(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\can\,\,be \,\, written\,\, as\,\,\\(\sqrt[3] {2x})-6\left(\sqrt[3]{x}\right)$

So, option c is correct

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3 years ago

Read 2 more answers

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AnnZ [28]

9514 1404 393

Answer:

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Step-by-step explanation:

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Here, the leading coefficient is 1 in each case, so the possible rational roots are plus or minus a divisor of the constant term.

9. The constant is -6. Divisors of 6 are 1, 2, 3, 6. The possible rational roots are ...

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A graphing calculator is useful for seeing if any of these values actually are roots of the equation. (The 4th-degree equation will have 2 complex roots.)

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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