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3 consecutive integers = x+(x+1)+(x+2) or 3x+3 (x is the smallest number)
(Consecutive means one after another)
So 3x+3 = 330.
Now subtract 3 from both sides.
(3x-3)=3x
(330-3)=327
The left side is 3x and the right side is 327.
The equation now is 3x=327.
Now divide each side by 3 (so x is isolated)
3x÷3=x
327÷3=109
The left side is x and the right side is 109.
The final equation is x=109.
Since x is the smallest of these integers we don't have to do anything else.
Okay, so let's check the answer now. 109+110+111=330.
So the smallest of the 3 consecutive numbers is 109.
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