YOoooO help muuee.?!?.!??.!?.

Mathematics

2 answers:

Stella [2.4K]3 years ago

8 0

the answer would be B!

wel3 years ago

4 0

The answer to this question is B. Use symbolab

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The LCM of 2 numbers is 60 and 1 of the numbers is 7 less than the other number. What are the numbers?

Phoenix [80]

Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.

Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:

discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)

and

-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)

Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.

Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.

5 0

3 years ago

Which one is bigger?<br>|-4| □ |-6|

Genrish500 [490]

Answer:

hello

Step-by-step explanation:

there is my answer

hope it helps