Question;
Assumption:
Let us assume Brandon's running speed is = 18.30 and
Ruben's running speed is = 16.50 and
Answer:
The two equations that can represent the relationship between the meters and second for Brandon and Ruben are;
Brandon → Y₁ = 18.3·X₁ and
Ruben → Y₂ = 16.5·X₂
Step-by-step explanation:
The equation is of the form
Y = 17.45·X
That is Amy ran Y meters in X seconds
Therefore we have
or the value 17.45 is the running speed of Amy
Therefore, where the running speed of Brandon is 18.30 and the running speed of Ruben is 16.50 we have
Y meters ran by Brandon in X seconds given by
Y₁ = 18.3·X₁ and
For Ruben we have Y meters ran in X seconds given by
Y₂ = 16.5·X₂.
Just divide 220 by 4 to get the answer. So the answer is 55.
Explanation:
220/4=55
If the drive needs to be completed in 4 hours and the drive is 220 miles then how much mph do they need to go
Miles/hours=miles per hour
Brainliest my answer if it helps you out
Answer:

Step-by-step explanation:
We want the equation of the line perpendicular to y=-3.
Notice that y=-3 is a horizontal line.
Therefore, in order to be perpendicular, our new equation must be vertical.
We know that it must pass through the point (2, -1).
Since it must be vertical, it must pass through the x-coordinate.
Therefore, our line must be:

It passes through (2, -1) and is a vertical line, so it’s perpendicular to y=-3.
12.321 kilograms are in 12,321 grams. Since it takes 1000 grams to make one kilogram, what ever amount of grams of anything you have, divide it by 1000, and that will show how much kilograms you have.
The value of f[ -4 ] and g°f[-2] are
and 13 respectively.
<h3>What is the value of f[-4] and g°f[-2]?</h3>
Given the function;


- f[ -4 ] = ?
- g°f[ -2 ] = ?
For f[ -4 ], we substitute -4 for every variable x in the function.

For g°f[-2]
g°f[-2] is expressed as g(f(-2))
![g(\frac{3x-2}{x+1}) = (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) = \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) = 13](https://tex.z-dn.net/?f=g%28%5Cfrac%7B3x-2%7D%7Bx%2B1%7D%29%20%3D%20%20%28%5Cfrac%7B3x-2%7D%7Bx%2B1%7D%29%20%2B%205%5C%5C%5C%5Cg%28%5Cfrac%7B3x-2%7D%7Bx%2B1%7D%29%20%3D%20%20%5Cfrac%7B3x-2%7D%7Bx%2B1%7D%20%2B%20%5Cfrac%7B5%28x%2B1%29%7D%7Bx%2B1%7D%5C%5C%5C%5Cg%28%5Cfrac%7B3x-2%7D%7Bx%2B1%7D%29%20%3D%20%20%5Cfrac%7B3x-2%2B5%28x%2B1%29%7D%7Bx%2B1%7D%5C%5C%5C%5Cg%28%5Cfrac%7B3x-2%7D%7Bx%2B1%7D%29%20%3D%20%20%5Cfrac%7B8x%2B3%7D%7Bx%2B1%7D%5C%5C%5C%5CWe%5C%20substitute%20%5C%20in%20%5C%20%5B-2%5D%20%5C%5C%5C%5Cg%28%5Cfrac%7B3x-2%7D%7Bx%2B1%7D%29%20%3D%20%20%5Cfrac%7B8%28-2%29%2B3%7D%7B%28-2%29%2B1%7D%5C%5C%5C%5Cg%28%5Cfrac%7B3x-2%7D%7Bx%2B1%7D%29%20%3D%20%20%5Cfrac%7B-16%2B3%7D%7B-2%2B1%7D%5C%5C%5C%5Cg%28%5Cfrac%7B3x-2%7D%7Bx%2B1%7D%29%20%3D%20%20%5Cfrac%7B-13%7D%7B-1%7D%5C%5C%5C%5Cg%28%5Cfrac%7B3x-2%7D%7Bx%2B1%7D%29%20%3D%20%2013)
Therefore, the value of f[ -4 ] and g°f[-2] are
and 13 respectively.
Learn more about composite functions here: brainly.com/question/20379727
#SPJ1