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3 years ago

What do you know about the slope of parallel lines?

1 answer:

8 0

The slope formula is amount risen over amount run. Look up the formula for a better demonstration. Also, it determines how steep a line is. Brainliest pls?

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3 years ago

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What is the y intercept of the function f(x)=-2/9x+1/3?

azamat

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4 0

3 years ago

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Y equals -2 over 5 x + 1 y-intercept

kipiarov [429]

Y = -2/5x + 1

I think your question is what is the y-intercept? It would be 1. -2/5 is the slope.

4 0

3 years ago

the company also discovered that it costs 30 to 2 widgets, 118 to produce 4 and 766 to produce 10 widgets. Find the total cost o

miv72 [106K]

We will first write cost function. As we are given three points here so we will use them to write quadratic function

$y = ax^{2} +bx+c$ ----------------------------------------(1)

So we will plug point (2,30) in it first ( for 2 widgets cost is 30)

So simply plug 30 in y place and 2 in x place in equation (1) as shown

$30 = a(2)^{2} +b(2)+c$

$30 = 4a +2b +c$ ----------------------------------------------(2)

Similarly plug next point (4,118) now in equation (1)

$118 = a(4)^{2} +b(4)+c$

$118 = 16a +4b +c$ ----------------------------------------------(3)

Similarly plug third point (10,766) now in equation (1)

$766 = a(10)^{2} +b(10)+c$

$766 = 100a +10b +c$ ----------------------------------------------(4)

Now we have to solve system of linear equations (2),(3) and (4) for a,b,c

We can use method of elimination

Subtract equation (3) - equation (2)

118 = 16a +4b +c

-(30 = 4a +2b +c)

----------------------------------------------------

88 = 12a +2b -----------------------------------(5)

Similarly subtract equation (4)-equation (3)

766 =100a +10b +c

-( 118 = 16a +4b +c)

--------------------------------------

648 = 84a + 6b ------------------------(6)

Now to eliminate b in equations (5) and (6) multiply equation (5) by -3 and then add to equation (6)

-3×(88 = 12a +2b)

-264 = -36a - 6b

648 = 84a + 6b

---------------------------------

384 = 48a

Now solve for a

$\frac{384}{48} = \frac{48a}{48}$

8 = a

Plug 8 in a place in equation (5) or (6) and solve for b as shown

88 = 12(8) +2b

88 = 96 + 2b

88 -96 = 96 +2b -96

-8 = 2b

$\frac{-8}{2} = \frac{2b}{2}$

-4 = b

now plug 8 in a place, -4 in b place in either of equations (2),(3) or (4) and solve for c

30 = 4(8) +2(-4) +c

30 = 32 -8 + c

30 = 24 + c

30 - 24 = 24 + c - 24

6 = c

So plugging values of a as 8, b as -4 and c as 6 in equation (1) we get

$y = 8x^{2} -4x+ 6$

So thats the cost function. So now for 6 widgets, plug 6 in x place in this equation and find y value

$y = 8(6)^{2} -4(6)+ 6$

y = 8(36) - 24 +6

y = 288 -24 +6

y = 270

So $270 is the cost for producing 6 widgets and thats the final answer

4 0

3 years ago

PLEASE HELP WITH B OR C ASAP ❤️

Monica [59]

Each angle of the equilateral triangle is 180/3 = 60 degrees. Each angle of the square is 90 degrees. Focus on the angles around the top vertex of the equilateral triangle. We have 2 angles from the square and one angle from the equilateral triangle, so 2*90+60 = 180+60 = 240 degrees is accounted for so far, leaving 360-240 = 120 degrees left over for the northernmost triangle.

The northernmost triangle is isosceles because the squares all have the same side lengths (due to the fact they match up with an equilateral triangle where all the sides are the same here as well). Isosceles triangles have congruent base angles, in this case both are x degrees. Add up the angles of this northernmost triangle and set this equal to 180. Solve for x.

x+120+x = 180

2x+120 = 180

2x = 180-120

2x = 60

x = 60/2

x = 30

=====================================================

The angle x combines with the 90 degree adjacent angle of the square to get 90+x = 90+30 = 120. Each interior angle of this odd hexagon is 120 degrees. Focus on the entire figure overall.

====================================================

The interior angles of any pentagon always add to 180(n-2) = 180(5-2) = 540 degrees. Assuming this is a regular pentagon, each interior angle of the regular pentagon is 540/5 = 108 degrees.

Focus on the northern most point on the pentagon. The angles attached to this point are the two square angles of 90 degrees each and the 108 degrees from the interior angle of a pentagon. We have 2*90+108 = 288 degrees so far, and 360-288 = 72 degrees left over for the bottom angle of the northern most triangle.

Again we have an isosceles triangle, so the base angles are both x

x+x+72 = 180

2x+72 = 180

2x = 180-72

2x = 108

x = 108/2

x = 54

And,

90+x = 90+54 = 144 represents each interior angle of this strange looking decagon.

4 0

3 years ago

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