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goblinko [34]
3 years ago
14

a glass triangular prism for a telescope is 5.5 inches long. each side of the prism´s triangular bases is 4 inches long and abou

t 3.46 inches high. About how much glass covers the surface of the prism?
Mathematics
1 answer:
adelina 88 [10]3 years ago
6 0
Multiply them all, that divide by 2
the answer is 38.06
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A study is conducted to determine if a newly designed text book is more helpful to learning the material than the old edition. T
Oksanka [162]

Answer:

The null and alternative hypotheses are:

H_{0}:\mu=75

H_{a} : \mu>75

Under the null hypothesis, the test statistic is:

t=\frac{\bar{x}-\mu}{\frac{s}{\sqrt{n}} }

Where:

\bar{x} =83 is the sample mean

s=9.8206 is the sample standard deviation

n=10 is the sample size

\therefore t= \frac{83-75}{\frac{9.8206}{\sqrt{10}} }

         =2.58

Now, we can find the right tailed t critical value at 0.01 significance level for df = n-1 = 10 - 1 = 9 using the t distribution table. The t critical value is given below:

t_{critical} =2.821

Since the test statistic is less than the t critical value, we therefore, fail to reject the null hypothesis and conclude that there is not sufficient evidence to support the claim that the people do better with the new edition.

7 0
3 years ago
Find the sum. Write your answer in simplest form.
Masteriza [31]

Answer:

19/20

Step-by-step explanation:

write all numerators above the common denominator 20

14+5/20

19/20

4 0
3 years ago
ABCD is a rectangle. What is the value of x?
ankoles [38]

Answer:

B

Step-by-step explanation:

Use the pythagorean theorem

a² + b² = c²

a² + 63² = 65²

a² + 3969 = 4225

a² = 256

a = 16

x = 16 meters

7 0
4 years ago
Read 2 more answers
A baseball is thrown in a parabolic arc. It's position above the ground at a given point in time can be represented by the quadr
SCORPION-xisa [38]

Answer:

The baseball reached 9 feet high above the ground

Step-by-step explanation:

The given quadratic function representing the position of the baseball above ground is p(t) = 1/2·g·t² + v₀·t + p₀

Where;

t ≥ 0

g = -32 ft./sec²

v₀ = The initial velocity

p₀ = The initial position

Given that when the ball is thrown, we have;

The initial, straight up, velocity, v₀ = 16 ft./sec

The initial position, p₀ = 5 ft.

Substituting the above values in the quadratic function representing the position of the baseball above ground, we have;

p(t) = 1/2·(-32)·t² + 16·t + 5 = 16·t - 16·t² + 5

At the maximum point, the rate of change of the height with time = 0, therefore;

dp(t)/dt = 0 = d(16·t - 16·t² + 5)/dt = 16 - 32·t

16 - 32·t = 0

16 = 32·t

t = 16/32 = 0.5 seconds

Therefore, the time takes to reach the maximum height = 0.5 seconds

The height (maximum) reached in 0.5 seconds is given as follows;

h(t) = 16·t - 16·t² + 5, from which we have;

h(0.5) = 16 × 0.5 - 16 × (0.5)² + 5 = 9

Therefore, the height baseball reached = 9 ft. above ground

7 0
3 years ago
100x^2-4=0<br> quick pls with all work
Finger [1]
4(5x+1)(5x-1) = 0

1. Take out the GCF (in this case, 4)
4(25x^2-1) = 0

2. This can be further factored. Factor the values within the parenthesis
4(5x + 1)(5x -1) = 0

4 0
3 years ago
Read 2 more answers
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