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aksik [14]
3 years ago
15

A function is shown in the table below.

Mathematics
1 answer:
MAXImum [283]3 years ago
4 0
The answer you will be needing is X+5=y
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A sign is hammered into a tree 2m from the trees base. if the tree is 10m tall and elongates 1m each year, how high will the sig
dlinn [17]
12m ?.......................
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3 years ago
16-2v+3 what is the answer pls help
djyliett [7]

Answer:

the answer is 19-2v combine like terms if not that then try this....

19-2y=0

-2y=-19

Then divide by -2

y=-19/-2

=9.5

4 0
3 years ago
Problem situation: Bernie spends $6.50 on ingredients and cups for his lemonade stand. He charges $1.50 for each cup of lemonade
salantis [7]

Answer:

Answer:

18 cups.

Step-by-step explanation:

We are given that Bernie spends $6.50 on ingredients and cups for his lemonade stand. He charges $1.50 for each cup of lemonade. Inequality that represents this situation: .

To find number of cups x to make a profit of at least  $20 we will use our given inequality.

Therefore, in order to make a profit of at least $20 Bernie need to sell 18 cups of lemonade.

3 0
3 years ago
Find the y-intercept of the line on the graph.​
horrorfan [7]
The y intercept is 2,0
4 0
4 years ago
An object is launched at 29.4 meters per
Lerok [7]

Answer:

The reasonable domain for the scenario is option 'a';

a) [0, 7]  

Step-by-step explanation:

For the projectile motion of the object, we are given;

The speed at which the object is launched, v = 29.4 meters per second

The height of the platform from which the object is launched, h = 34.3 meter

The equation for the height of the object as a function of time 'x' is given as follows;

f(x) = -4.9·x² + 29.4·x + 34.3

The domain for the scenario, is given by the possible values of 'x' for the function, which is found as follows;

At the height from which the object is launched, x = 0, and f(x) = 34.3

At the ground level to which the object can drop, f(x) = 0

∴ f(x) = -4.9·x² + 29.4·x + 34.3 = 0

-4.9·x² + 29.4·x + 34.3 = 0

By the quadratic formula, we have;

x = (-29.4 ± √(29.4² - 4 × (-4.9) × 34.3))/(2 × (-4.9)

∴ x = -1, or 7

Given that time is a natural number, we have the reasonable domain for the scenario as the start time when the object is launched, t = 0 to the time the object reaches the ground, t = 7

Therefore, the reasonable domain for the scenario is; 0 ≤ x ≤ 7 or [0, 7].

4 0
3 years ago
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