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jeyben [28]
3 years ago
5

Which of the following best classifies a quadrilateral with coordinates A(2, 6), B(5, 1), C(10, 4), and D(7, 9)? Rectangle Paral

lelogram Rhombus Square
Mathematics
1 answer:
IRINA_888 [86]3 years ago
3 0

Hey there! I'm happy to help!

This is a very fun problem to do. What you do is plot the four points on the graph and you connect the dots!

I cannot necessarily show you in text what it looks like but if you connect the dots you will get a square. But please try it out for yourself!

I hope that this helps! Have a wonderful day!

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Can't see the graph can you make it more clear?
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Logan made a profit of $210.00 as a mobile groomer. He charged $75.00 per appointment and received $35.00 in tips, but also had
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4 0
2 years ago
Round 27346 to 2 significant figures i need a step by step expansion
belka [17]

Answer:

27000

Step-by-step explanation:

We want to round 27346 to 2 significant figures.

Now, the number already has 5 significant figures, so to reduce it to 2 sig figures, we will have to reduce the 3 digits from the right to zero so that we can have just 2 significant figures by approximating.

Thus, 3 is less than 5 and so 7 cannot increase. Thus, we will have 27000 as the number when reduced to 2 significant figures.

5 0
3 years ago
HELP ME TO ANSWER THIS PLEASE JUST KINDA CONFUSED.
yulyashka [42]

Answer:

A = 5

B = 9

Step-by-step explanation:

This was very simple!

Nancy needs at least 15 boxes of travoprost but she only has 10. To find out how many she needs, we subtract 15 from 10 to get 5 boxes

Nancy also needs at least 12 boxes of latanoprost but she only has 3. To find out how many she needs, we subtract 12 from 3 to get 9 boxes

Therefore A = 5 boxes; B = 9 boxes

<em>PLEASE DO</em><em> </em><em>MARK ME</em><em> </em><em>AS BRAINLIEST</em><em> </em><em>IF MY</em><em> </em><em>ANSWER IS</em><em> </em><em>HELPFUL</em><em> </em><em>;</em><em>)</em>

3 0
3 years ago
Read 2 more answers
Derivative, by first principle<br><img src="https://tex.z-dn.net/?f=%20%5Ctan%28%20%5Csqrt%7Bx%20%7D%20%29%20" id="TexFormula1"
vampirchik [111]
\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}h

Employ a standard trick used in proving the chain rule:

\dfrac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\cdot\dfrac{\sqrt{x+h}-\sqrt x}h

The limit of a product is the product of limits, i.e. we can write

\displaystyle\left(\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\right)\cdot\left(\lim_{h\to0}\frac{\sqrt{x+h}-\sqrt x}h\right)

The rightmost limit is an exercise in differentiating \sqrt x using the definition, which you probably already know is \dfrac1{2\sqrt x}.

For the leftmost limit, we make a substitution y=\sqrt x. Now, if we make a slight change to x by adding a small number h, this propagates a similar small change in y that we'll call h', so that we can set y+h'=\sqrt{x+h}. Then as h\to0, we see that it's also the case that h'\to0 (since we fix y=\sqrt x). So we can write the remaining limit as

\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan\sqrt x}{\sqrt{x+h}-\sqrt x}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{y+h'-y}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{h'}

which in turn is the derivative of \tan y, another limit you probably already know how to compute. We'd end up with \sec^2y, or \sec^2\sqrt x.

So we find that

\dfrac{\mathrm d\tan\sqrt x}{\mathrm dx}=\dfrac{\sec^2\sqrt x}{2\sqrt x}
7 0
3 years ago
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