3^2 + 3 / 3
3^2 = 9
9 + 3 = 12
12/3 = 4
Hope this helps!!!
3(n+4)=1/2(6n+4)
2x3(n+4)=2x1/2(6n+4)
6(n+4)=1(6n+4)
6n+24=6n+4
24-4=6n-6n
20=O
Answer:
c^2=a^2+b^2
c is hypothesis b is abase h is a
15^2=x^2 +12^2
225-144 =x^2
81=x^2
x=9
X + (x+2) + (x+4) = 87
3x = 81
x = 27
So the longest side is 27+4 = 31