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Anastasy [175]
4 years ago
10

Evaluate x(– y + z) for x = –1, y = 2, and z = 5

Mathematics
2 answers:
Delicious77 [7]4 years ago
7 0
Ok so lets plug it in
-1(-2+5)
3+-5
=-2
raketka [301]4 years ago
7 0
I think its 2+-5 becuz its distribute property. if i got it wrong plz dont get mad. But i hope this helped have a great day!<span />
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Please HELP❗️40 points
Alekssandra [29.7K]

Answer:

<h3>Q1</h3>
  • This is acute angle since 75° < 90°
<h3>Q2</h3>
  • This is an isosceles triangle
<h3>Q3</h3>

<u>Exterior angle is the sum of non-adjacent interior angles:</u>

  • 4x + 7 + 6x - 9 = 118
  • 10x - 2 = 118
  • 10x = 120
  • x = 12

m∠L = 4*12 + 7 = 48 + 7 = 55°

<h3>Q4</h3>

<u>The triangles are congruent and corresponding sides are equal:</u>

  • 3x - 5 = 2x + 1
  • 3x - 2x = 1 + 5
  • x = 6

<u>Side lengths are:</u>

  • 3*6 - 5 = 13
4 0
3 years ago
If the surface area of a sphere is 4534.16cm squared what is the radius of the sphere
scoundrel [369]

Answer:

The surface area of a sphere is calculated by formula:

A = 4 x pi x radius^2

=> radius =  sqrt(A/(4 x pi) = sqrt(4534.16/(4 x pi)) = 19 (cm)

Hope this helps!

:)

5 0
4 years ago
Help i need help please
Molodets [167]

The coefficient would be 18. The exponent for g would be 18. The exponent for h would be 9.

Add the exponents of the same variable and multiply the coefficents.

3 0
3 years ago
Read 2 more answers
Jina, Chang, and Kevin sent a total of 130 text messages over their cell phones during the weekend. Chang sent 3 times as many m
Ronch [10]

Answer:

Let the no. of messages Jina send be x.

No. of messages Kevin send=x-5

No. of messages Chang send=3(x-5)

=3x-15

x+(x-5)+(3x-15)=130

x+x-5+3x-15=130

x+x+3x-5-15=130

5x-20=130

5x=130+20

=150

x=150÷5

=30

No. of messages Jina sent=30

No. of messages Kevin sent=30-5

=25

No. of messages Chang sent=3(30)-15

=90-15

=75

8 0
3 years ago
Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line. y = 4 − 1 2
MissTica

Answer:

{\dfrac{127 \pi}{12}

Step-by-step explanation:

The formula for the volume for a solid of revolution about the x-axis on an interval [a,b] is

\displaystyle V = \int_{a}^{b} \pi y^{2}dx

If y =  4 - ½x, a = 1, and b = 2,

\displaystyle V = \int_{1}^{2} \pi (4 - \frac{1}{2}x)^{2}dx = \pi \int_{1}^{2} \left(\dfrac{8-x }{2}\right)^{2}dx=\dfrac{\pi }{4}\int_{1}^{2} \left(8-x\right)^{2}dx\\\\=-\dfrac{\pi }{4}\times \dfrac{1}{3}\left[ 8 - x)^{3}\right]_{1}^{2}= -\dfrac{\pi }{12 }\left [512 - 192x + 24x^{2}-x^{3} \right ]_{1}^{2}\\\\=-\dfrac{\pi }{12}(512 - 384 +  96-8) + \dfrac{\pi }{12}(512 - 192 +24 -1)\\\\= -\dfrac{216\pi }{12} + \dfrac{343\pi }{12} = \mathbf{\dfrac{127 \pi}{12}\approx 33.25}

The solid looks like the graph below.

 

8 0
3 years ago
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