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lakkis [162]
3 years ago
7

A line passes through the points (p, a) and (p, –a) where p and a are real numbers and p ≠ 0. Describe each of the following. Ex

plain your reasoning.
1. slope of the line
2. equation of the line
3. y-intercept
4. slope of a line perpendicular to the given line
Mathematics
1 answer:
PolarNik [594]3 years ago
7 0
Since the x-coordinate does not change, we know immediately that this straight line is a vertical one.  It does not have a slope (div. by zero is undefined).

The equation of this vertical line is x=0.  

The line has no y-intercept.

A line perpend. to the given line has a slope of 0.
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A sign language club made $627.50 from selling popcorn at a festival. The popcorn cost the club $95.00. Which expression represe
Charra [1.4K]

Answer:

(627.50-95)/m

Step-by-step explanation:

The total value of money earned was $627.50. Then subtract the amount of money the popcorn cost, $95.00. This subtraction would make the difference of $532. This equation would be in parentheses because you have to get the difference before you can divide the profits among the club members. After you put that into parentheses, divide the difference by M. This will give you the equation (627.50-95.00)/m hope this helps!

4 0
3 years ago
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Klio2033 [76]
5/6 of the paper is devoted to news and pictures

first I made the fraction have equal denominators which was 6 by doing that I multiplyed the numerator and the denominator

1/2
1×3=3
2×3=6
therefore 1/2 being equivalent to 3/6


1/3
1×2=2
3×2=6
therefore 1/3 being equivalent to 2/6

now you would be able to add the numerators, so 2+3=5
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4 0
3 years ago
Which represents the solution(s) of the graphed system of equations, y = x2 – 2x and y = –2x – 1? (1, –1) (0, 0) and (0, –1) (0,
olganol [36]

ANSWER

No solution

EXPLANATION

The first equation is

y =  {x}^{2}  - 2x

and the second equation is

y =  - 2x  - 1

We equate the two equations to obtain;

{x}^{2}  - 2x =  - 2x - 1

This implies that

{x}^{2}  =  - 2x + 2x - 1

{x}^{2}  =  - 1

There is no real number whose square is -1.

Therefore, the equation has no solution.

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