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3 years ago

A square dance floor has a perimeter of 120 yards. What is the length of a diagonal of the dance floor?

Mathematics

1 answer:

Crazy boy [7]3 years ago

6 0

Answer:

Hey!

Your answer is C.42.4yd

Step-by-step explanation:

There are 2 ways you can work this on out...

1. Using Pythagoras Theorem...

= 30^2 + 30^2 = 1,800 (30^2=900 so you've added 2 of those to make 1,800)

= SQUARE ROOT THE ANSWER OF 1,800

$\sqrt{x} 1,800$ = 42.42640687119285‬

TO GET A MORE PRECISE ANSWER WE ROUND IT UP TO 1 decimal place

= 42.4 yd is the diagonal length of the dance floor!!

HOPE THIS HELPS!!

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marusya05 [52]

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3 years ago

How can you use the properties of operations to evaluate<br> this expression?<br> 18 + 4(28)

nirvana33 [79]

Answer:

Well on of the properties states that unless there are parenthesis, you multiply and divide first then you add and subtract. So, first we multiply 28*4 and that leaves use with 112, now if there is no more multiplication, division, or parentheses, and there's not. We can continue all we do is add 18+112 and we get our answer of 130.

6 0

2 years ago

Read 2 more answers

The larger of two numbers is 15 more than three times the smaller number. If the sum of the two numbers is 63, find the numbers

Amanda [17]

Answer:

The smaller number equals 12, the larger number equals 51.

Step-by-step explanation:

x + (3x + 15) = 63

Combine like terms.

4x + 15 = 63

Subtract 15 from both sides.

4x + (15 -15) = (63 - 15)

4x = 48

Divide both sides by 4.

4x/4 = 48/4

x = 12

Check answer.

12 + (3(12) + 15) = 63

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7 0

3 years ago

The center of a hyperbola is (−4,3) , and one vertex is (−4,7) . The slope of one of the asymptotes is 2.

Monica [59]

Answer:

The answer to your question is below

Step-by-step explanation:

C (-4, 3)

V (-4, 7)

asymptotes = 2 = $\frac{b}{a}$

- This is a vertical hyperbola, the equation is

$\frac{(y - k)^{2} }{a^{2} } + \frac{(x - h)^{2} }{b^{2} } = 1$

slope = 2

a is the distance from the center to the vertex = 4

b = 2(4) = 8

$\frac{(y - 3)^{2} }{4^{2} } + \frac{(x + 4)^{2} }{8^{2} } = 1$

$\frac{(y - 3)^{2} }{16} + \frac{(x + 4)^{2} }{64} = 1$

7 0

3 years ago

Read 2 more answers

taurus [48]

Answer:

$x^2 - 2x + 10$ , option B

Step-by-step explanation:

Complex numbers:

The most important relation that involves complex numbers is given by:

$i^2 = -1$

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

The solutions are:

$x_1 = 1 - 3i, x_2 = 1 + 3i$

We have to find the polynomial. All option have $a = 1$ . So

$(x - (1 - 3i))(x - (1 + 3i)) = x^2 - x(1 + 3i) - x(1 - 3i) + (1 - 3i)(1 + 3i) = x^2 - x -3ix - x + 3ix + 1^2 - (3i^2) = x^2 - 2x + 1 - 9i^2 = x^2 - 2x + 1 - 9(-1) = x^2 - 2x + 10$

The correct answer is given by option b.

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3 years ago