Solve these equations through the process of elimination and substitution

Mathematics

1 answer:

Inga [223]3 years ago

5 0

I have written out the steps to get to the answer of x=3, y=0

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lina2011 [118]

Answer:

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3 years ago

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Nicole tutors history. For each hour that she tutors she earns 50 dollars. Her earnings, (E) in dollars, after tutoring for (h)

dangina [55]

Answer:

$150

Step-by-step explanation:

Find how much Nicole earns for 3 hours by plugging in 3 as h in the function:

E(h) = 50h

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So, for tutoring for 3 hours, Nicole will earn $150

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Darlene has a balance of $3980 on a credit card with an APR of 22.8%. Paying off her balance in which of these lengths of time w

inna [77]

Answer:

The correct answer is D. 5 months

Step-by-step explanation:

Balance = P = $3980

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n is no. of times interest is calculated in one year n = 1

$Interest=P\cdot (1+\frac{r}{n\times 100})^{n\times time}\\\\\textbf{time = t = 8 months = }\frac{8}{12}\text{ years}\\\\Interest=3980\cdot (1+\frac{22.8}{1\times 100})^{1\times \frac{8}{12}}\\\\Interest=3980\times 1.228^{\frac{8}{12}}\\\\\implies Interest=\$\thinspace 4564.03\\\\\textbf{time = t = 6 months = }\frac{6}{12}\text{ years}\\\\Interest=3980\cdot (1+\frac{22.8}{1\times 100})^{1\times \frac{6}{12}}\\\\Interest=3980\times 1.228^{\frac{6}{12}}\\\\\implies Interest=\$\thinspace 4410.44$

$\textbf{time = t = 9 months = }\frac{9}{12}\text{ years}\\\\Interest=3980\cdot (1+\frac{22.8}{1\times 100})^{1\times \frac{9}{12}}\\\\Interest=3980\times 1.228^{\frac{9}{12}}\\\\\implies Interest=\$\thinspace 4642.82\\\\\textbf{time = t = 5 months = }\frac{5}{12}\text{ years}\\\\Interest=3980\cdot (1+\frac{22.8}{1\times 100})^{1\times \frac{5}{12}}\\\\Interest=3980\times 1.228^{\frac{5}{12}}\\\\\implies Interest=\$\thinspace 4335.60$