One number is 26 the other is 23
x+y=49
Y=x+3,X (now substitute it in the equation)
x+3+x=49
2x+3=49
2x=46. X=23
Y=x+3. Y=23+3 =26 for checking 23+26=49
To solve this problem, you must find a common denominator. First, you multiply the denominators together, then, multiply the numerator of the first fraction by the original denominator of the second fraction and vis-versa.
<span>3*4 = denominator of both
</span><span>2*4 = numerator of first fraction
</span><span>3*3 = numerator of second fraction
</span>
Your fractions should end up being 8/12 cups of raisins and 9/12 cup of almonds. You can now compare these fractions.
<span>Overall, there are 1/12 more almonds than raisins.</span>
1st quartile: 11
median: 38.50000
3rd quartile: 45
<h3>According to the given information:</h3>
- Order these numbers in increasing order: 6, 7, 15, 36, 41, 43, 47, 49
- There is a 38.5 median (it is the mean of 36 and 41 - the pair of middle entries).
- 6,7,15,36, or the left-most half of the data, make up the sample.
- The median of the lower half is 11, which is the first quartile (it is the mean of 7 and 15 - the pair of middle entries).
- 41, 43, 47, and 49, which are the data points in the upper half, are to the right of the median.
- The median of the upper half is 45 in the third quartile (it is the mean of 43 and 47 - the pair of middle entries).
- The biggest value deviates 10.5 from the median (49-38.5)
Measure descriptive statistics
1st quartile: 11
median: 38.50000
3rd quartile: 45
To know more about quartile visit:
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I understand that the question you are looking for is :
2 Drag the tiles to the boxes to form correct pairs. Match the values associated with this data set to their correct descriptions. {6, 47, 49, 15, 43, 41, 7, 36} first quartile 38.5 median 11 third quartile 10.5 the difference of the largest value and the median 45
Answer:
First of all, it's the Greatest to least! Second of all, 2/1, 8/9, 7/9, and 2/3.
Step-by-step explanation:
2/1 is 2, 8/9 is 1 more ninth than 7/9, and 2/3 is less third than 1.
a. Parameterize 
by
with 
.
b/c. The line integral of 
over is
d. Notice that we can write the line integral as
By Green's theorem, the line integral is equivalent to
where 
is the triangle bounded by , and this integral is simply twice the area of . is a right triangle with legs 2 and 5, so its area is 5 and the integral's value is 10.
