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3 years ago

A rectangular prism has a length of 5 meters, a width of 634 meters, and a height of 312 meters.

Mathematics

1 answer:

olga_2 [115]3 years ago

3 0

The answer is 405,076 meters.

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Can someone help me with these problems and show work please !!

Flauer [41]

Answer:

I have just wrote answers

7 0

2 years ago

Simplify the expression<br> 65-4^2 (10-2)+37 <br> please show all work

BartSMP [9]

Hello there!

$65-4^2 (10-2)+37 \\$

Explanation:

↓↓↓↓↓↓↓↓↓↓↓↓↓

I gave you a hint.

You had to used PEMDAS.

P-Parenthesis

E-Exponents

M-Multiply

D-Divide

A-Add

S-Subtract

First you had to calculate with parenthesis first.

$65-4^2(10-2)+37$

$65-4^2*8+37$

Then you calculate with exponents.

$4^2=4*4=16$

$65-16*8+37$

You had to multiply and divide you had go to left to right.

$16*8=128$

$65-128+37$

Then you add or subtract you had go to left to right.

$65-128+37=-26$

$=-26$

Answer⇒⇒⇒⇒⇒⇒=-26

Hope this helps!

Thank you for posting your question at here on Brainly.

Have a great day!

-Charlie

6 0

3 years ago

The figure shows the front side of a metal desk in the shape of a trapezoid.

Alenkinab [10]

Answer:

Area of trapezoid is $16ft^2$ .

Therefore, option 2nd is correct.

Step-by-step explanation:

We have been given both the sides a=3 and b=5.

And height that is h=4

We will use the formula find the area of trapezoid is:

$\frac{a+b}{2}\cdot h$

Substitute the formula we get:

$\frac{3+5}{2}\cdot 4$

$\Rightarrow \frac{8}{2}\cdot 4$

$\Rightarrow 16$ .

Area of trapezoid is $16ft^2$ .

Therefore, option 2nd is correct.

6 0

3 years ago

Read 2 more answers

I need to find the greatest common factor of <img src="https://tex.z-dn.net/?f=40s%5E3t%5E5" id="TexFormula1" title="40s^3t^5" a

solong [7]

Answer:

$\large\boxed{GCF(40s^3t^5,\ 2s^4t^4,\ 14s^6t^6)=2s^3t^4}$

Step-by-step explanation:

$40s^3t^5=\boxed2\cdot2\cdot2\cdot5\cdot \boxed{s\cdot s\cdot s}\cdot \boxed{t\cdot t\cdot t\cdot t}\cdot t\\\\2s^4t^4=\boxed2\cdot \boxed{s\cdot s\cdot s}\cdot s\cdot \boxed{t\cdot t\cdot t\cdot t}\\\\14s^6t^6=\boxed2\cdot7\cdot \boxed{s\cdot s\cdot s}\cdot s\cdot s\cdot s\cdot \boxed{t\cdot t\cdot t\cdot t}\cdot t\cdot t\\\\GCF(40s^3t^5,\ 2s^4t^4,\ 14s^6t^6)=\boxed2\cdot \boxed{s\cdot s\cdot s}\cdot\boxed{t\cdot t\cdot t\cdot t}=2s^3t^4$

7 0

3 years ago

Two boats started to move towards each other from two boat stations, located 30 miles apart. One boat moved at a speed of 3 mile

Ganezh [65]

Answer: <u>3 hours and 20 minutes</u>

Step-by-step explanation:

3x + 2(3)x = 30

3x + 6x = 30

9x = 30

9/9 = 30/9

x = 3 1/3 hours

6 0

2 years ago