Answer:
3.96mm/year
Step-by-step explanation:
Given that :
Given that:
Observed variation in water level over 6.2 years = - 13.64mm
Average annual trend shows rise in water level at 1.8 mm / year
difference between how much average water levels rose and how much the water level fell in the part of the river she observed?
Average Yearly observed variation :
Observed variation / number of years
-13.64mm / 6.2 years
= - 2.16 mm
Hence, observed yearly fall = - 2.16 mm
Yearly rise = 1.8mm / year
Difference :
( 1.8 mm/year) - (-2.16mm / year)
= (1.8 + 2.16) mm/year
= 3.96 mm/year
Answer:
Perpendicular(p)=21
base(b)=20
hypotenuse(h)=29
Step-by-step explanation:
Now by using the formula:
cos A=b/h
i.e 20 by 29
- 9 + 7
-2
if you need more details, please leave me a comment
The answer to your problem A=60
A.) P(defective | foo) = P(defective & foo)/P(foo)
4% = P(defective & foo)/30% . . . . . . . . . plug in the given data
0.04*0.30 = P(defective & foo) = 0.012 = 1.2%
The probability that a widget was produced at the foo factory and is defective is 1.2%.
b.) P(defective | foo) ≠ P(defective) (4% ≠ 5%), so the events P(defective) and P(foo) are NOT independent.
c.) P(foo | defective) = P(defective & foo)/P(defective)
P(foo | defective) = 1.2%/5% = 24%
The probability that a widget was produced at the foo factory given it is defective is 24%.
