You and a friend each randomly draw a card from a standard deck. What is the probability that at least one of you is holding a f
2 answers:
Answer:
0.24
Step-by-step explanation:
Total cards = 52
Face cards = heart {K,Q,J} , Spade {K,Q,J} , Club {K,Q,J} , Diamond{K,Q,J} = 12
Now we are given that You and a friend each randomly draw a card from a standard deck.
Probability that no one getting face card:
Favorable events = total cards - face cards = 52 -12= 40
Total cards = 52
So, probability that no one is getting face card =
Now we are supposed to find the probability that at least one of you is holding a face card
So, probability = 1 - probability that no one is getting face card
=1 - 0.76
= 0.24
So, probability that at least one of you is holding a face card is 0.24
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Answer:
y=2x+3
Step-by-step explanation:
first use the y2-y1/x2-x1 then use y=mx+b after
plug in 3 for y2 and 5 for y1
then plug in 0 for x2 and 1 for x1
=
and 2 is ur slope
___________________
now use y=mx+b
i usually use the first point but u can u anyone u want
plug in 1 for x
plug in 5 for y
and plug in 2 for m
5=2(1)+b
5=2+b
subtract 2 on both sides
5-2=3
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y=2x+3
hope this helps
Answer:
The largest even integer is 0
Step-by-step explanation:
Given as :
The sum of four consecutive even number = - 12
Let The first even number = 2 x
The second even number = (2 x + 2)
The third even number = (2 x + 4)
The fourth even number = (2 x + 6)
<u>According to question</u>
sum of four consecutive even number = - 12
Or, 2 x + (2 x + 2) + (2 x + 4) + (2 x + 6) = - 12
Or, (2 x + 2 x + 2 x + 2 x) + (2 + 4 + 6) = - 12
Or, 8 x + 12 = - 12
Or, 8 x = - 12 - 12
Or, 8 x = - 24
∴ x =
i.e x = - 3
now, putting the value of x
The first even number = 2 × - 3 = - 6
The second even number = (2 × - 3 + 2) = - 6 + 2 = - 4
The third even number = (2 × - 3 + 4) = - 6 + 4 = - 2
The fourth even number = (2 × - 3 + 6) = - 6 + 6 = 0
So, The largest even integer = 0
Hence, The largest even integer is 0 Answer