Question

Raphael graphed the functions g(x)=x+2 and f(x)=x−1. How many units below the y-intercept of g(x) is the y-intercept of f(x)? A coordinate plane with 2 lines drawn. The first line is labeled f(x) and passes through the points (0, negative 1) and (1, 0). The second line is labeled g(x) and passes through the points (negative 2, 0) and (0, 2). −3 units −1 units 2 units 3 units

Answer 1

Answer:

3 units below the y-intercept of g(x) is the y-intercept of f(x)

Step-by-step explanation:

Answer 2

Answer:

3 units below the y-intercept of g(x) is the y-intercept of f(x)

Step-by-step explanation:

$g(x)=x+2$ and $f(x)=x-1$

In f(x)= mx+b the y intercept is b

In $g(x)=x+2$, the y intercept value is 2

In $f(x)=x-1$, the y intercept value is -1

the difference in y intercept is +2-(-1)=+3

3 units below the y-intercept of g(x) is the y-intercept of f(x)