The graph of f(x) = x3 + 6x2 + 12x + 8 is shown. Based on the graph, how many real number solutions does the equation x3 + 6x2 +
12x + 8 = 0 have?
2 answers:
SEE ATTACHED IMAGE TO OBSERVE THE GRAPH OF THE FUNCTION.
For this case, the first thing we should see are the cut points with the x axis.
We note that the graph cuts to the x-axis at x = -2
Therefore, x = -2 is the real solution to the polynomial.
Also this function:
x3 + 6x2 + 12x + 8
It can be rewritten as:
(x + 2) ^ 3
From where we conclude that its roots are:
x = -2 (with multiplicity 3)
Answer:
the equation x3 + 6x2 + 12x + 8 = 0 have:
x = -2
As a real solution with multiplicity 3.
For this case, the first thing we should see are the cut points with the x axis.
We note that the graph cuts to the x-axis at x = -2
Therefore, x = -2 is the real solution to the polynomial.
Also this function:
x3 + 6x2 + 12x + 8
It can be rewritten as:
(x + 2) ^ 3
From where we conclude that its roots are:
x = -2 (with multiplicity 3)
Answer:
the equation x3 + 6x2 + 12x + 8 = 0 have:
x = -2
As a real solution with multiplicity 3.
You might be interested in
Answer:
Find the attached
Step-by-step explanation:
To graph the given function, we would need to obtain pairs of points (x, f(x)). We can let x be;
-5, -4, -3, 3, 4, 5
we simply substitute each value of x in the given function to obtain the value of the function corresponding to the given x value;
when x = -5, f(-5) = |-5+2| - 3 = 0
when x = -4, f(-4) = |-4+2| - 3 = -1
when x = -3, f(-3) = |-3+2| - 3 = -2
when x = 3, f(3) = |3+2| - 3 = 2
when x = 4, f(4) = |4+2| - 3 = 3
when x = 5, f(5) = |5+2| - 3 = 4
The graph of the function is as shown in the attachment below.
