The graph of f(x) = x3 + 6x2 + 12x + 8 is shown. Based on the graph, how many real number solutions does the equation x3 + 6x2 +
12x + 8 = 0 have?
2 answers:
SEE ATTACHED IMAGE TO OBSERVE THE GRAPH OF THE FUNCTION.
For this case, the first thing we should see are the cut points with the x axis.
We note that the graph cuts to the x-axis at x = -2
Therefore, x = -2 is the real solution to the polynomial.
Also this function:
x3 + 6x2 + 12x + 8
It can be rewritten as:
(x + 2) ^ 3
From where we conclude that its roots are:
x = -2 (with multiplicity 3)
Answer:
the equation x3 + 6x2 + 12x + 8 = 0 have:
x = -2
As a real solution with multiplicity 3.
For this case, the first thing we should see are the cut points with the x axis.
We note that the graph cuts to the x-axis at x = -2
Therefore, x = -2 is the real solution to the polynomial.
Also this function:
x3 + 6x2 + 12x + 8
It can be rewritten as:
(x + 2) ^ 3
From where we conclude that its roots are:
x = -2 (with multiplicity 3)
Answer:
the equation x3 + 6x2 + 12x + 8 = 0 have:
x = -2
As a real solution with multiplicity 3.
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TheThe area of the shaded region if the radius of the outer circle is 4 and the radius of the inner circle is 2 is 12π.
<h3>Area of the shaded region</h3>Area of a circle = πr²
r =radius of the circle
Area of the outer circle:
Area of the outer circle = π(4)²
Area of the outer circle = 16π
Area of the inner circle:
Area of the inner circle = π (2)²
Area of the inner circle = 4 π
Area of the shaded Region :
Area of the shaded Region = 16π - 4 π
Area of the shaded Region = 12π
Therefore the area of the shaded region if the radius of the outer circle is 4 and the radius of the inner circle is 2 is 12π.
Learn more about area of the shaded region here: brainly.com/question/19577281
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