Ann, Chang, and Kareem sent a total of
1 answer:
It is given in the question that
Ann, Chang, and Kareem sent a total of 89 text messages over their cell phones during the weekend. Ann sent 9 fewer messages than Chang. Kareem sent 3 times as many messages as Ann.
Let number of messages Chang sent be x. And Ann sent 9 fewer than Chang, so Ann sent (x-9) messages. And Kareem sent 3 times as many messages as Ann, so Kareem sent 3(x-9) messages.
And the total messages are 89. That is
Combining like terms
So Chang sent 25 messages, Ann sent
And Kareem sent
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Answer:
Step-by-step explanation:
a) the sample point of the random experiment is 36
b) (1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)
Only (1,1) will sum to give 2.
(1,2) and (2,1) will sum up to give 3.
(1,3), (2,2) (3,1) will sum up to give 4.
(1,4) (2,3) (3,2) (4,1) will sum up to give 5.
(1,5) (2,4) (3,3) (4,2) (5,1) will sum up to give 6
(1,6) (2,5) (3,4) (4,3) (5,2) (6,1) will sum up to give 7
(2,6) (3,5) (4,4) (5,3) (6,2) will sum up to give 8
(3,6) (4,5) (5,4) (6,3) will sum up to give 9
(4,6) (5,5) (6,4) will sum up to give 10
(5,6) (6,5) will sum up to give 11
(6,6) 1ill sum up to give 12.
c) probability of obtaining a value of 5 = (number of possible times 5 will occur)/ (total outcome) =
d) probability of obtaining a value of 8 or greater =
e) yes, since the total number is 11 and probability of obtaining odd number is and probability of obtaining even number is
.
P(odd)P(even)
f) emprical method was used