Answer:
neither
Step-by-step explanation:
<em>Both statements are correct.</em>
If matrix 1 has dimensions (r1, c1) and matrix 2 has dimensions (r2, c2), their product can be formed if c1 = r2. The resulting product matrix will have dimensions (r1, c2).
The inverse of matrix A =
is
The given matrix is A = ![\left[\begin{array}{cc}2&2&1&3\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%262%261%263%5C%5C%5Cend%7Barray%7D%5Cright%5D)
The inverse of a matrix is given by
...(1)
Now, determinant of matrix A is
|A| = 
= (3)(2) - (2)(1)
= 6 - 2
= 4
Now, adjoint A will be
= 3
= -1
= -2
= 2
AdjA = 
Now, substituting the values of |A| and AdjA in equation (1), we get
Therefore,
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Ok to start this problem you must list two numbers that add to 14
7 and 7
9 and 5
10 and 4
6 and 8
those are the numbers that we will use for now..
Now multiply each pair of numbers and see which one equals 45
7 * 7 = 49, no
9 * 5 = 45, YES
10 * 4 = 40, No
6 * 8 = 48, No
The numbers discovered are 9 and 5