Which expression is equivalent to 5.9−3.8 ?

Can anyone help? Ignore what I wrote on there.

Marrrta [24]

Answer:

The number is 38.........

5 0

3 years ago

A number cube is rolled. What is the probability of rolling a 2,3, or 5?

Liula [17]

Well if the number cube goes up to 6 like most number cubes, then the probability would be 3/6 because there are 3 numbers that you want to roll (2, 3, and 5) out of 6 total numbers (1-6). Then 3/6 can be further simplified to 1/2. So the answer should be 1/2.

4 0

3 years ago

I cant figure out the answer pls explain

Kazeer [188]

0.3(x - 2y) + 0.5x - y
0.3x - 0.6y + 0.5x - y
(0.3x + 0.5x) + (-0.6y - y)
0.8x + 1.6y
This means the answer is B.
Feel free to ask me any questions about method of solving in the comments :)

6 0

3 years ago

Help please!! will give brainiest :))

jeyben [28]

Answer:

81(x + 2y)(x - 2y)

Step-by-step explanation:

$81 {x}^{2} - 324 {y}^{2} \\ \\ = {(9x)}^{2} - {(18y)}^{2} \\ \\ = (9x + 18y)(9x - 18y) \\ \\ = 9(x + 2y) \times 9(x - 2y) \\ \\ = 81(x + 2y)(x - 2y)$

7 0

3 years ago

Read 2 more answers

The lengths of pregnancies are normally distributed with a mean of days and a standard deviation of days. a. Find the probabilit

Alik [6]

Answer:

a) The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of $Z = \frac{X - \mu}{\sigma}$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

b) We have to find X when Z has a p-value of $\frac{a}{100}$ , and X is given by: $X = \mu - Z\sigma$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In this question:

Mean $\mu$ , standard deviation $\sigma$

a. Find the probability of a pregnancy lasting X days or longer.

The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of $Z = \frac{X - \mu}{\sigma}$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

b. If the length of pregnancy is in the lowest a%, then the baby is premature. Find the length that separates premature babies from those who are not premature.

We have to find X when Z has a p-value of $\frac{a}{100}$ , and X is given by: $X = \mu - Z\sigma$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

8 0

3 years ago