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Gnoma [55]
3 years ago
9

What is the perimeter of triangle ABC with the points A=(5,-1) B=(-1, 1) C=(0,-3), rounded to the nearest tenth.

Mathematics
1 answer:
enyata [817]3 years ago
3 0

the perimeter is 15.8 units


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How do I do this please help me
ratelena [41]

Answer: I think it might be (0,8)

Step-by-step explanation:

6 0
3 years ago
Raymond needs to cover the entire surface area of the square based pyramid with paper what is the minimum amount of paper he wil
ra1l [238]

Answer: 408 sq ft

Step-by-step explanation: You would need to use the surface area formula SA = 1/2LP + B. Note that L is the slant height, P is the perimeter of the base, and B is the area of the base. 11 is the slant height as shown in the image above, p is 48 since you add 12 + 12 + 12 + 12, and the area of the square will be 144 since 12*12 = 144. Once you substitute the numbers in their correct place, you should get SA = 1/2 (11)(48)+144 which gives you 408 sq ft. Hope this helps!

3 0
3 years ago
this question is pretty easy i just dont understand, so if you could answer asap that would really help :)
alexdok [17]
The second choice should be correct

6 0
3 years ago
A man 2 m high observes the angle of elevation to the top of a building to be 71° and the angle of depression to the bottom of t
Yuki888 [10]

Answer:

The building is 13.91 m tall

Step-by-step explanation:

The parameters given are;

Angle of elevation to the top of the building = 71°

Angle of depression to the bottom of the building = 26°

Height of the man = 2  m

Therefore, the sight of the man, the man's height, and the distance of the man from the building forms a triangle where:

The hypotenuse side = The sight of the man to the bottom of the building

Hence;

In ΔABC, A being at the eye level or head level of the man, B at the foot and C at the bottom of the building

∴ ∠A + Angle of depression to the bottom of the building = 90°

∠A = 90° - 26° = 64°

∠B = 90° and ∠C = 26° (Sum of angles in a triangle)

Tan(C) = \frac{AB}{BC}

Distance of the man from the building = BC

Tan(26) = \frac{2}{BC}

BC= \frac{2}{ Tan(26) } = 4.1 \, m

Given that the angle of elevation to the top of the building = 71°, we have;

ΔAET

Where:

A is at the head level of the man,

E is the point on the building directing facing the man and

T is the top of the building

Hence AE = BC and ∡TAE = 71°

TE + AB= The height of the building

Tan(TAE) = \dfrac{TE}{AE}\\\\Tan(71) = \dfrac{TE}{4.1}

∴ TE = tan(71°) × 4.1 = 11.91 m

Hence the height of the building = 11.91 + 2 = 13.91 m.

4 0
3 years ago
2h − 3 = 3 Need some help
QveST [7]

Answer: Let's solve your equation step-by-step.

2h−3=3

Step 1: Add 3 to both sides.

2h−3+3=3+3

2h=6

Step 2: Divide both sides by 2.

2h/2 = 6/2

h = 3.

8 0
3 years ago
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