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3 years ago

What is the volume of a right circular cylinder with a base diameter of 17.5 ft and a height of 24.5 ft?

Mathematics

2 answers:

Natasha_Volkova [10]3 years ago

3 0

Answer:

The volume of a right circular cylinder with a base diameter of 17.5 ft and a height of 24.5 ft is:

5889.95 ft³

Step-by-step explanation:

We are given a base diameter of a right circular cylinder as :

d = 17.5 ft.

hence radius of cylinder i.e. r =d/2 = 8.75 ft.

height of the cylinder = 24.5 ft.

now we know that volume of cylinder i.e. V is given by :

V = πr²h

putting the value of r and h in the given formula to obtain the volume

V = 3.14×(8.75)²×24.5

= 5889.95 ft³

hence, the volume of a right circular cylinder with a base diameter of 17.5 ft and a height of 24.5 ft is:

5889.95 ft³

IgorLugansk [536]3 years ago

3 0

Answer:

5889.95

Step-by-step explanation:

volume of a cylinder is the area of the base times the height. To find the area of the base it is $a=\pi r^{2}$ Since they give diameter you need to find radius by dividing. 17.5 divided by 2 is 8.75. the area is $76.5625\pi$ then times height it is $1875.78125\pi$ then, like they said, use 3.14 as pi. Round to get 5889.95

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there are 15 rafts available for people to use on the adventure river ride. each raft holds 12 people. the park runs this ride 3

3241004551 [841]

540 people can ride the wild river in 1 hour if all of the rafts are used and each raft is full

<u>Solution:</u>

Given, There are 15 rafts available for people to use on the adventure river ride.

Each raft holds 12 people.

Then, total people capacity over all rafts = 15 x 12 = 180 people.

The park runs this ride 3 times each hour.

We have to find how many people can ride the wild river in 1 hour if all of the rafts are used and each raft is full?

Then, <em>total people count who take ride = number of rides x number of people per ride </em>

= 3 x 180 = 540

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3 years ago

Write 17,924 in expanded form

vesna_86 [32]

Answer:

10,000 + 7,000 + 900 + 20 + 4

Step-by-step explanation:

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3 years ago

Read 2 more answers

A water tank has a radius 5 feet and height 11 feet. How much water can it hold?

Semmy [17]

The water tank hold 863.50 $ft^{3}$ of water.

<h3>What is Volume of cylinder?</h3>

The volume of a cylinder is the number of unit cubes (cubes of unit length) that can be fit into it. It is the space occupied by the cylinder as the volume of any three-dimensional shape is the space occupied by it.

The water tank is in the shape of cylinder whose radius = 5 feet

and, height= 11 feet

Volume of water tank = $\pi r^{2} h$

= 3.14 * 5 * 5 * 11

= 3.14*25*11

= 863.50 $ft^{3}$

Hence the water tank hold 863.50 $ft^{3}$ of water.

Learn more about Volume of cylinder here:

brainly.com/question/16788902

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2 years ago

I didn’t learn about this can you help me with this

arlik [135]

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3 years ago

Find d for the arithmetic series with S17=-170 and a1=2

Irina18 [472]

So, we know the sum of the first 17 terms is -170, thus S₁₇ = -170, and we also know the first term is 2, well

$\bf \textit{ sum of a finite arithmetic sequence}\\\\
S_n=\cfrac{n(a_1+a_n)}{2}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
----------\\
n=17\\
S_{17}=-170\\
a_1=2
\end{cases}
\\\\\\
-170=\cfrac{17(2+a_{17})}{2}\implies \cfrac{-170}{17}=\cfrac{(2+a_{17})}{2}
\\\\\\
-10=\cfrac{(2+a_{17})}{2}\implies -20=2+a_{17}\implies -22=a_{17}$

well, since the 17th term is that much, let's check what "d" is then anyway,

$\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
n=17\\
a_{17}=-22\\
a_1=2
\end{cases}
\\\\\\
-22=2+(17-1)d\implies -22=2+16d\implies -24=16d
\\\\\\
\cfrac{-24}{16}=d\implies -\cfrac{3}{2}=d$

6 0

3 years ago