Question

Solve the following quadratic equation using the quadratic formula and then choose the correct solution set. 6x2 - 7x + 2 = 0

Answer 1

Answer:

Solutions of the quadratic equation are $\dfrac{2}{3},\dfrac{1}{2}$

Step-by-step explanation:

The given quadratic equation is,

$6x^2 - 7x + 2 = 0$

The quadratic formula is,

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

Here,

$a = 6,b=-7,c=2$

Putting the values,

$x=\dfrac{-(-7)\pm \sqrt{(-7)^2-4\cdot 6\cdot 2}}{2\cdot 6}$

$=\dfrac{7\pm \sqrt{49-48}}{12}$

$=\dfrac{7\pm \sqrt{1}}{12}$

$=\dfrac{7\pm 1}{12}$

$=\dfrac{7+ 1}{12},\dfrac{7-1}{12}$

$=\dfrac{8}{12},\dfrac{6}{12}$

$=\dfrac{2}{3},\dfrac{1}{2}$

Answer 2

6x^2 - 7x + 2 = 0
(3x-2)(2x-1) = 0

3x-2 = 0
x = 2/3

2x-1=0
x=1/2

answer: x=1/2 and x =2/3