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3 years ago

15

The hypotenuse is the longest side of a right triangle and is always opposite the right angle. The other sides of the right tria

ngle are called the _____ of the triangle.

1 answer:

Elanso [62]3 years ago

3 0

They are called "legs" :)

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Slove for g<br> 3/16= -5/4 +g

PSYCHO15rus [73]

Answer:

+g=3/16+5/4

the answer : 3/16+5/4

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2 years ago

Find all real solutions of the equation. <br> x4/3 − 7x2/3 + 10 = 0

BlackZzzverrR [31]

Solve by Factoring x^(2/3)-7x^(1/3)+10=0
x
2
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−
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x
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x
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x
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+
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Rewrite
x
2
3
x
2
3
as
(
x
1
3
)
2
(
x
1
3
)
2
.
(
x
1
3
)
2
−
7
x
1
3
+
10
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(
x
1
3
)
2
-
7
x
1
3
+
10
=
0
Let
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1
3
u
=
x
1
3
. Substitute
u
u
for all occurrences of
x
1
3
x
1
3
.
u
2
−
7
u
+
10
=
0

8 0

3 years ago

J= 6 for 15 - j= 21<br> What’s the answer

Ann [662]

Answer:

15+6=21

15-(-6) = 21

5 0

3 years ago

Read 2 more answers

1 over 8 added 5 times equals

leonid [27]

Answer:

5/8 or 41/8

Step-by-step explanation:

If you mean 1/8 x 5, then that equals 5/8

If mean 1/8 + 5, then that equals 41/8

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3 years ago

Of 560 marbles in a bag, 65% are red and the rest are blue. After 28 red marbles are replaced with blue ones, how many blue marb

jonny [76]

Answer: The answer is 400 blue marbles.

Step-by-step explanation: Given that there are 560 marbles in a bag, out of which 65% are red and rest are blue.

So, number of red marbles is

$n_r=65\%\times 560=\dfrac{65}{100}\times 560=364,$

and number of blue marbles is

$n_b=560-364=196.$

Now, if 28 red marbles are replaced by blue marbles, the the new number of red and blue marbles will be

$n_r^\prime=364-28=336~~~\textup{and}~~~n_b^\prime=196+28=224.$

Now, to get 65% of the marbles blue, we need to add some more blue marbles to the bag. Let 'x' number of blue marbles are added to the bag, then

$65\%\times (560+x)=224+x\\\\\Rightarrow \dfrac{65}{100}\times (560+x)=224+x\\\\\Rightarrow 13(560+x)=20(224+x)\\\\\Rightarrow 7280+13x=4480+20x\\\\\Rightarrow 7x=2800\\\\\Rightarrow x=400.$

Thus, 400 blue marbles need to be added to the bag.

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3 years ago

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