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3 years ago

Determine the coordinates of the x-intercept of the function shown in the graph. A) (-6, 0) B) (-2, 0) C) (0, -2) D) (0, -6)

Mathematics

1 answer:

ozzi3 years ago

6 0

Can I see the graph in order to help

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Evaluate the difference quotient for the given function. Simplify your answer.

nasty-shy [4]

I suppose you mean

$f(x) = \dfrac{x+5}{x+1}$

Then

$f(3) = \dfrac{3+5}{3+1} = \dfrac84 = 2$

and the difference quotient is

$\dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5}{x+1}-2}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5-2(x+1)}{x+1}}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{-x+3}{(x+1)(x-3)} \\\\ \dfrac{f(x)-f(3)}{x-3} = \boxed{-\dfrac{x-3}{(x+1)(x-3)}}$

If it's the case that x ≠ 3, then (x - 3)/(x - 3) reduces to 1, and you would be left with

$\dfrac{f(x)-f(3)}{x-3}\bigg|_{x\neq3} = -\dfrac1{x+1}$

4 0

3 years ago

Trucks in a delivery fleet travel a mean of 80 miles per day with a standard deviation of 30 miles per day. The mileage per day

bulgar [2K]

Answer: 0.1037

Step-by-step explanation:

Given : Mean : $\mu=80\text{ miles per day}$

Standard deviation : $\sigma = 30\text{ miles per day}$

The formula to calculate the z-score is given by :-

$z=\dfrac{x-\mu}{\sigma}$

For x = 97 miles per day ,

$z=\dfrac{97-80}{30}\approx0.57$

For x = 107 miles per day ,

$z=\dfrac{97-80}{30}=0.9$

The P-value = $P(0.57$

$=0.8159398-0.7122603=0.1036795\approx0.1037$

Hence, the probability that a truck drives between 97 and 107 miles in a day = 0.1037

6 0

3 years ago

To find an approximate value for a number

Nitella [24]

Remove the negative sign usually. Hope this helps!

7 0

3 years ago

Pls this is timed thank you

statuscvo [17]

I believe that is Khan academy from what I can see so no no I don’t believe it is timed, they do know all the timings but that won’t affect the score

4 0

4 years ago

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A retirangle has an area of 40 units.the lenght is 6 units greater then the width

slega [8]

40 units multiply by 6 units equal 240 units

3 0

3 years ago

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