Question

If a population is in Hardy–Weinberg equilibrium, when is the number of heterozygotes at its most?

Answer 1

Answer:

B) when the frequency of dominant alleles is equal to the frequency of recessive alleles

Explanation:

The equation for Hardy–Weinberg equilibrium is:

$p^{2} +2pq+q^{2}$;

where p=frequency of dominant alleles; q=frequency of recessive alleles and 2pq is the number of heterozygotes.

So, in order to maximize 2pq, p must be equal to q, and because p-q=1, we can conclude that 2pq max = 2*0.5*0.5=0.5 or 50%

A) when the frequency of dominant alleles is more than the frequency of recessive alleles: Homozygous dominant will be prevalent

C) when the frequency of dominant alleles is less than the frequency of recessive alleles: Homozygous recessive will be prevalent

Answer 2

I would go with the letter 
B- when the frequency of dominant alleles is equal to the frequency of recessive alleles.
Hope that this helps!!! :)