Answer:
The weight of watermelon at the end of the trip is <u>500 kg.</u>
Step-by-step explanation:
Given:
The weight of watermelons is 1000kg.
At the beginning of the trip watermelon is 99% of the weight:
99% of 1000kg


kg
Now, at the end of the trip it is 98% of weight. So, let
kg of water has been evaporated. So, remaining weight of the watermelon is
.
If
kg of water is removed, then the amount of water left is
.
As per question, water now weighs 98% of the total weight. So,
98% of (
) = 


(Bringing like terms on one side)

Therefore, the weight of watermelon at the end of the trip is given as:
Weight =
= 1000 - 500 = 500 kg
Therefore, the watermelon weighs 500 kg at the end of trip.