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max2010maxim [7]
3 years ago
13

Please help With the following question

Mathematics
1 answer:
Vikki [24]3 years ago
4 0
The equation youre using is y=mx+b

b is the y int which 3 and the slope between the points is 5/2 so your equation is y=5/2x+3
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Monique had $15. After paying for 6 pounds of squid, she had $3 left. Find the cost of 1 pound of squid.
katovenus [111]
12/6 which is 2$ per pound of squid
6 0
3 years ago
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5. A hockey player whose initial speed is 8.1 m/s increases his speed to 8.6 m/s in order to get to
balu736 [363]

Answer:

0.1m/s²

Step-by-step explanation:

the explanation is in the picture

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5 0
3 years ago
A school needs 5,000 to buy new books for the library. So far the school has raised 75%
ohaa [14]

Answer:

Results are below.

Step-by-step explanation:

Giving the following information:

Total money needed= $5,000

Percentage raised= 75%

<u>To calculate the amount collected and the difference required, we need to use the following formulas:</u>

Total collected= 5,000*0.75

Total collected= $3,750

Difference= 5,000 - 3,750

Difference= $1,250

4 0
3 years ago
For a circle with a radius of 15 cm, what is the length of an arc intercepted by an angle measuring 120°?
slega [8]

Answer: 31.43 cm

Step-by-step explanation:

The length of an arc  is calculated using the formula:

\frac{theta}{360} X 2\pir

where : theta is the angle in degree

r = radius

If the angle is given in Radian , the length can be calculated using the formula:

L = r∅

Since , the angle is given in degree , we will use the first formula.

L = \frac{theta}{360} X 2\pir

L = \frac{120}{360} X 2 X π X 15

L = \frac{1}{3} X 2 X \frac{22}{7} X 15

L = \frac{660}{21}

L = 31.42857143

L ≈ 31.43 cm

5 0
3 years ago
In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal dist
Tcecarenko [31]

Answer:

a. 0.7291

b. 0.9968

c. 0.7259

Step-by-step explanation:

a. np and n(1-p) can be calculated as:

np=23\times 0.48\\\\=11.04\\\\n(1-p)=23(1-0.52)\\\\=11.96

#Both np and np(1-p) are greater than 5, hence, normal approximation is most appropriate:

\mu_x=11.04\\\\\sigma^2=np(1-p)=0.48\times 0.52\times 23=5.7408

#Define Y:

Y~(11.04,5.7408)

P(X\leq 12)\approx P(Y\leq 12.5)\\\\P(Z\leq \frac{(12.5-11.04)}{\sqrt{5.7408}})=\\\\=1-0.2709\\\\=0.7291

Hence, the probability of 12 or fewer is 0.8291

b. The  probability that 5 or more fish were caught.

#Using normal approximation:

P(X \geq 5) \approx P(Y \geq 4.5) = P(Z \geq\frac{ (4.5-11.04)}{\sqrt{(5.7408)}})\\\\=1-0.0032\\\\=0.9968

Hence, the probability of catching 5+ is 0.9968

c. The probability of between 5 and 12 is calculated as;

-From b above P(X\geq 5)=0.9968 and a ,P(X\leq 12)=0.7291

P(5\leq X\leq 120\approx P(4.5\leq Y\leq  12.5)\\\\=0.7291-(1-0.9968)\\\\=0.7259

Hence, the probability of between 5 and 12 is 0.7259

4 0
3 years ago
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