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4 years ago

Please help With the following question

Mathematics

1 answer:

Vikki [24]4 years ago

4 0

The equation youre using is y=mx+b

b is the y int which 3 and the slope between the points is 5/2 so your equation is y=5/2x+3

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Monique had $15. After paying for 6 pounds of squid, she had $3 left. Find the cost of 1 pound of squid.

katovenus [111]

12/6 which is 2$ per pound of squid

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3 years ago

Read 2 more answers

5. A hockey player whose initial speed is 8.1 m/s increases his speed to 8.6 m/s in order to get to

balu736 [363]

Answer:

0.1m/s²

Step-by-step explanation:

the explanation is in the picture

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3 years ago

A school needs 5,000 to buy new books for the library. So far the school has raised 75%

ohaa [14]

Answer:

Results are below.

Step-by-step explanation:

Giving the following information:

Total money needed= $5,000

Percentage raised= 75%

<u>To calculate the amount collected and the difference required, we need to use the following formulas:</u>

Total collected= 5,000*0.75

Total collected= $3,750

Difference= 5,000 - 3,750

Difference= $1,250

4 0

3 years ago

For a circle with a radius of 15 cm, what is the length of an arc intercepted by an angle measuring 120°?

slega [8]

Answer: 31.43 cm

Step-by-step explanation:

The length of an arc is calculated using the formula:

$\frac{theta}{360}$ X 2 $\pi$ r

where : theta is the angle in degree

r = radius

If the angle is given in Radian , the length can be calculated using the formula:

L = r∅

Since , the angle is given in degree , we will use the first formula.

L = $\frac{theta}{360}$ X 2 $\pi$ r

L = $\frac{120}{360}$ X 2 X π X 15

L = $\frac{1}{3}$ X 2 X $\frac{22}{7}$ X 15

L = $\frac{660}{21}$

L = 31.42857143

L ≈ 31.43 cm

5 0

3 years ago

In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal dist

Tcecarenko [31]

Answer:

a. 0.7291

b. 0.9968

c. 0.7259

Step-by-step explanation:

a. np and n(1-p) can be calculated as:

$np=23\times 0.48\\\\=11.04\\\\n(1-p)=23(1-0.52)\\\\=11.96$

#Both np and np(1-p) are greater than 5, hence, normal approximation is most appropriate:

$\mu_x=11.04\\\\\sigma^2=np(1-p)=0.48\times 0.52\times 23=5.7408$

#Define Y:

Y~(11.04,5.7408)

$P(X\leq 12)\approx P(Y\leq 12.5)\\\\P(Z\leq \frac{(12.5-11.04)}{\sqrt{5.7408}})=\\\\=1-0.2709\\\\=0.7291$

Hence, the probability of 12 or fewer is 0.8291

b. The probability that 5 or more fish were caught.

#Using normal approximation:

$P(X \geq 5) \approx P(Y \geq 4.5) = P(Z \geq\frac{ (4.5-11.04)}{\sqrt{(5.7408)}})\\\\=1-0.0032\\\\=0.9968$

Hence, the probability of catching 5+ is 0.9968

c. The probability of between 5 and 12 is calculated as;

-From b above $P(X\geq 5)=0.9968$ and a , $P(X\leq 12)$ =0.7291

$P(5\leq X\leq 120\approx P(4.5\leq Y\leq 12.5)\\\\=0.7291-(1-0.9968)\\\\=0.7259$

Hence, the probability of between 5 and 12 is 0.7259

4 0

3 years ago