Question

If f(x)=4x^2 and g(x)=x+1, find (fog)(x)

Answer 1

Answer: The value of $(f_\circ g)(x)$  is  $4(x+1)^2$  .

Step-by-step explanation:

Given: $f(x) = 4x^2 \text { and } g(x) = x+1$

To find: $(f_\circ g)(x)$

As we know it is composition function which means that  g(x) function is in f(x) function.

So we have

$(f_\circ g) (x) = f[g(x)]$

$\Rightarrow( f_\circ g)(x)= f(g(x)) = 4(g(x))^2$

Now substitute the value of g(x) we get

$(f_\circ g)(x)= 4(x+1)^2$

Hence, the value of $(f_\circ g)(x)$  is  $4(x+1)^2$  .