To fill out a sign chart, you will need to use test numbers before and after each of the function's zeros and ______.

Mathematics

2 answers:

likoan [24]3 years ago

4 0

<span>To fill out a sign chart, you will need to use test numbers before and after each of the function's zeros and vertical asymptotes.

A sign chart is a chart which help in solving polynomial inequalities.</span>

kkurt [141]3 years ago

4 0

Answer with explanation:

→Sign charts are mainly used for solving Inequality.

→Sign charts are also used to determine in which interval function is increasing and in which interval it is decreasing.That is concept of Increasing and Decreasing Phenomenon is used in functions.

→In sign chart,we substitute real numbers after and before Zero of the inequality in the function to check which side on the number line or inside which interval the inequality is satisfied.

→So, to fill out a sign chart, you will need to use test numbers before and after each of the function's zeros and in the given Function (Polynomial).

Whether these numbers satisfy the Inequality or not to find the interval.

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Choose the graph that correctly corresponds to the equation y=4

Lera25 [3.4K]

Graph 1 is y = 4.

You can tell this because no matter what point you pick on that line, the ordered pair will contain the number 4 for y. You can also tell because y = a number graphs are always horizontal lines.

3 0

3 years ago

Read 2 more answers

5(2x - 3) + 2 (3x + 1)

astraxan [27]

<span> 1/3(2x - 3) + 1 = 1/4(3x + 5) - 2
2x/3 - 3/3 + 1 = 3x/4 + 5/4 - 2
2x/3 - 1 + 1 = 3x/4 + 5/4 - 2
2x/3 - 3x/4 - 0 = 3x/4 - 3x/4 + 5/4 - 2
2x*4/3*4 - 3x*3/4*3 = 0 + 5*1/4*1 - 2*4/1*4
8x/12 - 9x/12 = 5/4 - 8/4
(8x - 9x)/12 = (5 - 8)/4
-x/12 = -3/4
-x/12 * 12 = -3/4 * 12
-x = -36/4
-x * -1 = -36/4 * -1
x = 36/4
x = 9
Done

For check the answer
let x = 9
1/3(2[9] - 3) + 1 = 1/4(3[9] + 5) - 2
1/3(18 - 3) + 1 = 1/4(27 + 5) - 2
1/3(15) + 1 = 1/4(32) - 2
15/3 + 1 = 32/4 - 2
15/3 + 3/3 = 32/4 - 8/4
18/3 = 24/4
6 = 6
therefor
x = 9 is a correct answer</span>

6 0

3 years ago

Sketch the curve with the given vector equation. Indicate with an arrow the direction in which t increases. r(t) = 4 cos(t)i + 4

slega [8]

Answer:

The equation to this question is " $x^2+y^2=16$ "

Step-by-step explanation:

Given value:

$\to r(t) = 4 \cos (t)i + 4 sin(t)j + k\\where \\\\\to x(t)= 4 \cos t\\\to y(t) = 4 \sin t\\\to z(t)=1\\$

$\to x^2+y^2= 16 \cos^2 t +16 \sin^2 t\\\\\to x^2+y^2= 16 (\cos^2 t +\sin^2 t)\\\\\therefore (\cos^2 t +\sin^2 t =1)\\\\\to x^2+y^2= 16 (1)\\\\\to x^2+y^2= 16\\\\\to z=1$