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3 years ago

Which relationship describes angles 1 and 2?

Mathematics

1 answer:

kupik [55]3 years ago

5 0

Answer:

Supplementary angles

Adjacent angles

Step-by-step explanation:

They add up to a straight line, which is 180 degrees, therefore they are supplementary.

They also share a side and the corner point, hence adjacent.

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How many baseballs would fit into a box that has the dimensions (3*5)*2

Snezhnost [94]

3*5= 15

15*2= 30

30 baseballs

5 0

3 years ago

What is equivalent to 1/2 (6x + 12 + 3)? Is it A. 18x + 36 - 9 B. 2x + 4 - 1 C. 2x + 12 - 3 D. 18x + 12 - 3

Kobotan [32]

Answer choice A is correct

6 0

2 years ago

I need help with this ASAP plzzzzz

miss Akunina [59]

Answer:

23. $\frac{4\sqrt{3} }{3}$

24. $\frac{7\sqrt{3}}{3}$

25. $6\sqrt{3}$

26. $\frac{10\sqrt{3} }{3}$

27. $14$

28. $4\sqrt{3}$

Step-by-step explanation:

To solve these i used SOHCAHTOA

$sin=\frac{opposite}{adjacent}\\ cos=\frac{adjacent}{hypotenuse} \\tan=\frac{opposite}{adjacent}$

23.

Find the missing side using Tangent

$tan(30)=\frac{x}{4}$

$4*tan(30)=x$

$\frac{4\sqrt{3} }{3}$

24.

Find the missing side using Tangent

$tan(30)=\frac{x}{7}$

$7*tan(30)=x$

$\frac{7\sqrt{3}}{3}$

25.

Find the missing side using Tangent

$tan(30)=\frac{x}{18}$

$18*tan(30)=x$

$6\sqrt{3}$

26.

Find the missing side using Tangent

$tan(30)=\frac{x}{10}$

$10*tan(30)=x$

$\frac{10\sqrt{3} }{3}$

27.

Find the missing side using Tangent

$tan(30)=\frac{x}{14\sqrt{3} }$

$(14\sqrt{3}) *tan(30)=x$

$14$

28.

Find the missing side using Tangent

$tan(30)=\frac{x}{12}$

$12*tan(30)=x$

$4\sqrt{3}$

5 0

3 years ago

Which decimal number is equal to 318 ? 0.167 0.16¯ 0.16¯¯¯¯ 0.167¯¯¯¯¯

skad [1K]

Answer:

3/18 = 1/6 =.16666666.....

.16(would be repeating)

your choice D and A are the same, and choice C and B are the same!

hope this helps!

7 0

3 years ago

What is the value of x?<br><br>enter your answer in the box<br><br>X__

vfiekz [6]

<h3>Answer: x = 5</h3>

=====================

Work Shown:

Angle Bisector Theorem

9/(2x-1) = 15/3x

9*3x = 15(2x-1) ... cross multiply

27x = 30x-15

27-30x = 30x-15-30x ... subtract 30x from both sides

-3x = -15

-3x/(-3) = -15/(-3) .... divide both sides by -3

x = 5

6 0

3 years ago