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3 years ago

A packing crate measures 3 feet by 12 feet by 7 feet. what is the area of its smallest side

1 answer:

5 0

The packing crate measures 3 feet by 12 feet by 7 feet (volume). To find the area of the smallest side, multiply the two smaller numbers

3 x 7 = 21

21 feet² is the area of the smallest side

hope this helps

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Several paint mixtures are made by mixing blue paint and white paint. Paint Colors Blue Paint White Paint Mixture A 5 cups 12 cu

Flura [38]

The correct answer is option B which is mixture B will have the highest ratio of blue paint.

<h3>What is a ratio?</h3>

In mathematics, ratios are used to determine the relationship between two numbers it indicates how many times is one number to another number.

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The given ratios are:-

Mixture A = $\dfrac{5}{12} = 0.41$

Mixture B = $\dfrac{6}{6}= 1$

Mixture C = $\dfrac{4}{12}= 0.33$

Mixture B = $\dfrac{5}{6}=0.83$

Here the ratio of mixture B is the highest among all the options available.

Therefore the correct answer is option B which is mixture B will have the highest ratio of blue paint.

To know more about ratios follow

brainly.com/question/2328454

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4 0

2 years ago

3(x 2) 11 is greater than 20

Allushta [10]

3(x+2)+11>20
minus 11 both sides
3(x+2)>9
divide both sides by 3
x+2>3
minus 2 both sides
x>1

4 0

3 years ago

Find , , and if and terminates in quadrant .

ioda

sin2x =12/13

cos2x = 5/13

tan2x = 12/5

STEP - BY - STEP EXPLANATION

What to find?

• sin2x

• cos2x

• tan2x

Given:

tanx = 2/3 = opposite / adjacent

We need to first make a sketch of the given problem.

Let h be the hypotenuse.

We need to find sinx and cos x, but to find sinx and cosx, first determine the value of h.

Using the Pythagoras theorem;

hypotenuse² = opposite² + adjacent²

h² = 2² + 3²

h² = 4 + 9

h² =13

Take the square root of both-side of the equation.

h =√13

This implies that hypotenuse = √13

We can now proceed to find the values of ainx and cosx.

Using the trigonometric ratio;

$\sin x=\frac{opposite}{\text{hypotenuse}}=\frac{2}{\sqrt[]{13}}$ $\cos x=\frac{adjacent}{\text{hypotenuse}}=\frac{3}{\sqrt[]{13}}$

And we know that tanx =2/3

From the trigonometric identity;

sin 2x = 2sinxcosx

Substitute the value of sinx , cosx and then simplify.

$\sin 2x=2(\frac{2}{\sqrt[]{13}})(\frac{3}{\sqrt[]{13}})$ $=\frac{12}{13}$

Hence, sin2x = 12/13

cos2x = cos²x - sin²x

Substitute the value of cosx, sinx and simplify.

$\begin{gathered} \cos 2x=(\frac{3}{\sqrt[]{13}})^2-(\frac{2}{\sqrt[]{13}})^2 \\ \\ =\frac{9}{13}-\frac{4}{13} \\ =\frac{5}{13} \end{gathered}$

Hence, cos2x = 5/13

tan2x = 2tanx / 1- tan²x

$\tan 2x=\frac{2\tan x}{1-\tan ^2x}$ $=\frac{2(\frac{2}{3})}{1-(\frac{2}{3})^2}$ $=\frac{\frac{4}{3}}{1-\frac{4}{9}}$ $=\frac{\frac{4}{3}}{\frac{9-4}{9}}$ $=\frac{\frac{4}{3}}{\frac{5}{9}}$ $=\frac{4}{3}\times\frac{9}{5}=\frac{4}{1}\times\frac{3}{5}=\frac{12}{5}$