Hello!

Use PEMDAS (order of operations) to solve:
-4 · [3 + (-5)²] ÷ 7
Square -5:
-4 · [3 + 25] ÷ 7
Add the numbers inside of the parenthesis:
-4 · [28] ÷ 7
Multiply -4 and 28:
-112 ÷ 7
Divide:
= -16.
(-2x + 4y)(3x - 7y) = -6x^2 - 28y^2 + 12yx
Answer:
Step-by-step explanation:
vertex form of quadratic: y = a ( x − h ) ^ 2 + k
h= -2 , k = -2
y=a(x+2)^2-2
Substitute (-1,1)
1=a(-1+2)^2-2
a=3
y=3(x+2)^2-2
Expanding and give
y=3x^2+12x+10