Answer:
1.the program is moved from secondary storage to memory.
Explanation:
Secondary storage media generally have greater storage capacity than RAM (random access memory), for this reason the data and program are stored there.
but ram memories are much faster, for example, a solid state disk (SSD) with SATA III connection can have read and write speeds of approximately 500 MB/s, while a DDR III RAM can have speeds between 12 and 18 GB/S, that is, more than 20 times faster.
So that the flow of data at the time of running a program is optimal, the data from the secondary storage unit is copied to the RAM and this ensures that the speed at which the programs run is at least 20 times faster, and our processes run better.
Answer:
Following are the code to the given question:
#include <iostream>//header file
using namespace std;
class Window //defining a class Window
{
private:
int width, height;//defining integer variable
public:
friend ostream& operator << (ostream& stm, Window& width)//defining a friend function that takes two parameters
{
return stm<<"a ("<<width.width<<" x "<<width.height<<") window"; //use return keyword that return its values
}
Window(int width, int height): width(width), height(height)//defining parameterized constructor that inherit width and height in its parameters
{}
};
int main() //Main method
{
Window w(80,90);//calling class constructor
cout<<w;//print object value
return 0;
}
Output:
a (80 x 90) window
Explanation:
In the above code, a class "Window" is defined that uses a friend function "ostream& operator" is declared that uses the "ostrea&" as a data type to hold two-variable "stm and w" in its parameter, and declared the parameterized constructor to hold value by inheriting width and height in its parameters.
Inside the main method, a class object is created that calls the constructor and uses the print method to print object value.
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