Write a function with this prototype:
1 answer:
Answer:
Following are the code to this question:
#include <iostream> //defining header file
using namespace std;
void numbers(ostream &outs, const string& prefix, unsigned int levels); // method declaration
void numbers(ostream &outs, const string& prefix, unsigned int levels) //defining method number
{
string s; //defining string variable
if(levels == 0) //defining condition statement that check levels value is equal to 0
{
outs << prefix << endl; //use value
}
else //define else part
{
for(char c = '1'; c <= '9'; c++) //define loop that calls numbers method
{
s = prefix + c + '.'; // holding value in s variable
numbers(outs, s, levels-1); //call method numbers
}
}
}
int main() //defining main method
{
numbers(cout, "THERBLIG", 2); //call method numbers method that accepts value
return 0;
}
Output:
please find the attachment.
Explanation:
Program description:
- In the given program, a method number is declared, that accepts three arguments in its parameter that are "outs, prefix, levels", and all the variable uses the address operator to hold its value.
- Inside the method a conditional statement is used in which string variable s and a conditional statement is used, in if the block it checks level variable value is equal to 0. if it is false it will go to else block that uses the loop to call method.
- In the main method we call the number method and pass the value in its parameter.
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Answer:
The output is: Your cost is 100
Explanation:
Given
The above code snippet
and
Required
Determine the output of the code
if cost < 70 or cost > 150
The above condition checks if cost is less than 70 or cost is greater than 150
This condition is false because 100 is neither less than 70 nor is it greater than 150
So, the else statement will be executed.
discount = cost
Which means
discount = 100
So, the print instruction will print: Your cost is 100