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3 years ago

14

the graph shows the total number of hours katrina worked over a 10-day period. during which one-day interval did she work the mo

st hours?

1 answer:

liraira [26]3 years ago

8 0

Answer:

4 to 5

Step-by-step explanation:

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5. The superintendent of the local school district claims that the children in her district are brighter, on average, than the g

anygoal [31]

Answer:

We conclude that children in district are brighter, on average, than the general population.

Step-by-step explanation:

We are given the following data set:

105, 109, 115, 112, 124, 115, 103, 110, 125, 99

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{1117}{10} = 111.7$

Sum of squares of differences = 642.1

$S.D = \sqrt{\frac{642.1}{49}} = 8.44$

We are given the following in the question:

Population mean, μ = 106

Sample mean, $\bar{x}$ = 111.7

Sample size, n = 10

Alpha, α = 0.05

Sample standard deviation, s = 8.44

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 106\\H_A: \mu > 106$

We use one-tailed(right) t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{111.7 - 106}{\frac{8.44}{\sqrt{10}} } = 2.135$

Now,

$t_{critical} \text{ at 0.05 level of significance, 9 degree of freedom } = 1.833$

Since,

$t_{stat} > t_{critical}$

We fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

We conclude that children in district are brighter, on average, than the general population.

4 0

3 years ago

5300 round to the nearest thousand

AleksAgata [21]

5,000
is 300 closer to 100 or 1000?
or
is 3 closer to 1 or 10?

6 0

3 years ago

Read 2 more answers

Solve for c <br><br> a= b+c/d

castortr0y [4]

B+c/d=a subtract b from both sides

c/d=a-b multiply both sides by d

c=d(a-b) or if you prefer

c=ad-bd

Note: if you meant a=(b+c)/d, multiply both sides by d

b+c=ad subtract b from both sides

c=ad-b

4 0

3 years ago

Eight f subtract three f plus two plus five equals

Zolol [24]

Answer:

5f + 7

Step-by-step explanation:

8f-3f+2+5

8f-3f is 5f and 2 + 5 is 7

5f+7

6 0

3 years ago

Read 2 more answers

Five cards are selected without replacement from a pack of 52 playing cards. What is the probability of exactly 3 hearts?

irga5000 [103]

There are 13 total hearts in the deck, which leaves 39 non-hearts. You're drawing a hand of five cards, so the probability of getting exactly 3 hearts is

$\dfrac{\binom{13}3\binom{39}2}{\binom{52}5}=\dfrac{2717}{33320}$

as required.

3 0

3 years ago