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erastova [34]
4 years ago
7

Help me??? Please it’s urgent

Mathematics
2 answers:
Elodia [21]4 years ago
8 0

The answer is option 2.

DiKsa [7]4 years ago
4 0

Answer:

\tt\cfrac{\sqrt{14}}{6}

Step-by-step explanation:

\tt\sqrt{\cfrac{7}{18}}= \cfrac{\sqrt{7}}{\sqrt{18}}=\cfrac{\sqrt{7}}{3\sqrt{2}}=\cfrac{\sqrt{7}\cdot\sqrt{2}}{3\sqrt{2}\cdot\sqrt{2}}=\cfrac{\sqrt{7\cdot2}}{3\cdot2} =\cfrac{\sqrt{14}}{6}

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Identify the slope and y-intercept of: y= 1/2x - 6
kkurt [141]

Answer:

Slope: 1/2

Y-intercept: -6

7 0
3 years ago
Read 2 more answers
7. If Donna works 8 hours and earns
krek1111 [17]
Y = 25 times x
or you could write it as
y=25x
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hope this helps!
5 0
3 years ago
Help i cant figure this out:(
stealth61 [152]

Answer:

6-2=4

31/5 x 8 = 248/40

15/8 x 5 = 75/40

248-75=173

4 13/40

answers in order

6-2=4

6 1/5 - 1 7/8 = 4 13/40

Hope this helps

Step-by-step explanation:

8 0
3 years ago
Given the image of the right triangle below, choosing angle A as the reference angle, label which of the three sides of the tria
alina1380 [7]

Answer:

c is the hypotenuse

a is the leg opposite

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Step-by-step explanation:

The hypotenuse is the line across the right angle

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B is the adjacent one.

3 0
3 years ago
Air pressure may be represented as a function of height (in meters) above the
denis-greek [22]

Answer: OPTION C.

Step-by-step explanation:

<h3> The complete exercise is: "Air pressure may be represented as a function of height (in meters) above the surface of the Earth, as shown below:</h3><h3>  P(h) =P_0e^{-0.00012h} </h3><h3> In this function P_o   is the air pressure at the surface of the earth, and h is the height above the surface of the Earth, measured in meters. At what height will the air pressure equal 50% of the air pressure at the surface of the Earth"</h3><h3></h3>

Given the following function:

P(h) =P_0e^{-0.00012h}

In order to calculate at what  height the air pressure will be equal 50% of the air pressure at the surface of the Earth, you can follow these steps:

1. You need to substitute P(h)=0.5P_o into the function:

0.5P_o=P_0e^{-0.00012h}

2. Finally, you must solve for h.

Remember the following property of logarithms:

ln(b)^a=a*ln(b)\\\\ln(e)=1

Then, you get this result:

0.5P_o=\frac{P_o}{e^{0.00012h}}\\\\(0.5P_o)(e^{0.00012h})=P_o\\\\e^{0.00012h}=\frac{P_o}{0.5P_o}\\\\ln(e)^{0.00012h}=ln(2)\\\\0.00012h*1=ln(2)\\\\h=\frac{ln(2)}{0.00012}\\\\h=5576.2

7 0
4 years ago
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