Find all real zeros of the function Y = -9x - 1.
2 answers:
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Answer:
16.15% probability that exactly 3 of them would function
Step-by-step explanation:
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
Probability of each system working:
4 components, which means that
Each has a 30% probability of failing, so
For the system to work, all 4 components have to work. This is P(X = 4).
0.2401 probability of a system working.
If you have 7 of these systems, what is the probability that exactly 3 of them would function?
Now 7 systems, so
0.2401 probability of a system working.
We have to find P(X = 3).
16.15% probability that exactly 3 of them would function
None of those describe this function.
It's not a constant function, because it is not equal to a constant (something that isn't a variable)
It doesn't show direct variation, because it can't be represented in the form
y = kx.
It isn't an absolute value function because the absolute value isn't taken anywhere.
If it was an absolute value function it would look something like this:
It isn't a greatest integer function, because the greatest integer isn't taken anywhere.
If it was a greatest integer function it would look something like this:
Are you sure you typed that question right?
It's not a constant function, because it is not equal to a constant (something that isn't a variable)
It doesn't show direct variation, because it can't be represented in the form
y = kx.
It isn't an absolute value function because the absolute value isn't taken anywhere.
If it was an absolute value function it would look something like this:
It isn't a greatest integer function, because the greatest integer isn't taken anywhere.
If it was a greatest integer function it would look something like this:
Are you sure you typed that question right?