How many times can a honeybee beat its wings in one hour
2 answers:
Answer:
828000 times
Step-by-step explanation:
The flight of honeybees is very peculiar and has kept the scientists confused for a very long time. It is peculiar because the way they flap their wings used to be considered aerodynamically unstable and not fit for flying. But they do fly and flap their wings faster.
They beat their wings 230 times per second. That means in one hour they will beat the wings
= 828000 times
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Answer: 4 seconds
Step-by-step explanation:
Given: The function can be used to model the height of the ball where t is the time in seconds after the ball kicked and h(t) is the height in feet.
Differentiate the given function with respect to t , we get
Put h'(t)=0
Also,
By second derivative test, h(t) is maximum at t=4.
Hence, the time in Devon which the ball reaches it maximum height = 4 seconds
Slope-intercept form:
y = mx + b
"m" is the slope, "b" is the y-intercept (the y value when x = 0) or (0,y)
To find "m", you can use the slope formula and plug in the two points:
(2,3) = (x₁ , y₁)
(0,9) = (x₂ , y₂)
m = -3
y = -3x + b
To find "b", you can plug in one of the points into the equation (however they already gave you the y-intercept (0,9) or 9)
(2,3)
y = -3x + b
3 = -3(2) + b
3 = -6 + b
9 = b
y = -3x + 9
Answer:
x=10.8
Step-by-step explanation:
the image is the working out. hope this helps.
