Answer:
5
Step-by-step explanation:
Given that:
Total maximum amount that the owner wishes to spend = $20000
Average price of each car = $4000
To find:
How many cars that the owner can expect to buy?
Solution:
Total number of cars that the owner can expect to buy can be found by dividing the total money available with the owner with the average price of each car.
i.e.
We have the following values as given in the question statement:
Total money available = $20000
Average price of car = $4000
Therefore, the answer is:
The owner can expect to buy 5 number of cars.
<u>Answer:</u>
<em>Option D : $153</em>
<u>This is how I got that:</u>
9:30 AM to 1:15 PM = 3 hours and 45 minutes
The first hour charges $15 and for the remaining 2 hours and 45 minutes
Mr. Anand is charged 36$. Remember it says that each additional hour <em>or part thereof, </em>so the 2 hours and 45 minutes is considered 3 hours.
So our total for one paddle boat is <u>$51 </u>
<u />
But Mr. Anand hired <em>three</em> boats so we simply times 51 by 3 and get our solution to the problem:
<u>Mr. Anand must pay $153 or Option D</u>
<u></u>
<em>~That's All Folks~</em>
<em>-Siascon</em>
Answer:
The ratio between two values A and B is just the quotient between these two values:
ratio = A/B
a) $280 in 7m
Here the ratio is:
$280/7m = $40/m
This also can be read as:
$40 per meter.
b) 105 miles in 2 hours
Here the ratio is:
105mi/2h = 52.5 mi/h
This also can be read as:
52.5 miles per hour
c) $33 for 5lb
The ratio is:
$33/5lb = $6.6/lb
This can be read as:
$6.6 per pound.
d) 50 pages in 2 hours
the ratio is:
(50 pages)/2h = 25 pages/h
this can be read as:
25 pages per hour.
I don't have the measurements, but the lqbel would be a rectangle so you need to find its length and height (the length being the circumference of the can and the height being the height of the can)
True, because the standard deviation describes how far, on average, each observation is from the typical value. A larger standard deviation means that observations are more distant from the typical value, and therefore, more dispersed.
